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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) (4.0 atm, 5.0 L, 245 K) with a change in internal energy, AU = 30.0 L atm. The change in enthalpy (AH) of the process in L atm is:
a.40.0
b. 42.3
c.44.0
d. not defined, because pressure is not constant.
why not the answer is d?
Most Upvoted Answer
One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 ...
Introduction:
In this problem, we are given the initial and final states of a non-ideal gas and the change in internal energy. We are asked to determine the change in enthalpy of the process and whether it is defined or not.

Given:
Initial state: P1 = 2.0 atm, V1 = 3.0 L, T1 = 95 K
Final state: P2 = 4.0 atm, V2 = 5.0 L, T2 = 245 K
Change in internal energy: ΔU = 30.0 L atm

Formula:
The change in enthalpy (ΔH) of a process can be calculated using the equation:
ΔH = ΔU + Δ(PV)

Solution:
To calculate the change in enthalpy, we need to calculate the change in pressure-volume product (Δ(PV)).

Step 1: Calculate the initial pressure-volume product (P1V1):
P1V1 = (2.0 atm)(3.0 L) = 6.0 L atm

Step 2: Calculate the final pressure-volume product (P2V2):
P2V2 = (4.0 atm)(5.0 L) = 20.0 L atm

Step 3: Calculate the change in pressure-volume product (Δ(PV)):
Δ(PV) = P2V2 - P1V1
Δ(PV) = 20.0 L atm - 6.0 L atm
Δ(PV) = 14.0 L atm

Step 4: Calculate the change in enthalpy (ΔH):
ΔH = ΔU + Δ(PV)
ΔH = 30.0 L atm + 14.0 L atm
ΔH = 44.0 L atm

Conclusion:
The change in enthalpy (ΔH) of the process is 44.0 L atm. Therefore, the correct answer is option 3: 44.0. The answer is defined because we were able to calculate the change in enthalpy using the given information.
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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) (4.0 atm, 5.0 L, 245 K) with a change in internal energy, AU = 30.0 L atm. The change in enthalpy (AH) of the process in L atm is: a.40.0 b. 42.3 c.44.0 d. not defined, because pressure is not constant. why not the answer is d?
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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) (4.0 atm, 5.0 L, 245 K) with a change in internal energy, AU = 30.0 L atm. The change in enthalpy (AH) of the process in L atm is: a.40.0 b. 42.3 c.44.0 d. not defined, because pressure is not constant. why not the answer is d? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) (4.0 atm, 5.0 L, 245 K) with a change in internal energy, AU = 30.0 L atm. The change in enthalpy (AH) of the process in L atm is: a.40.0 b. 42.3 c.44.0 d. not defined, because pressure is not constant. why not the answer is d? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) (4.0 atm, 5.0 L, 245 K) with a change in internal energy, AU = 30.0 L atm. The change in enthalpy (AH) of the process in L atm is: a.40.0 b. 42.3 c.44.0 d. not defined, because pressure is not constant. why not the answer is d?.
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