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The enthalpy, internal energy during a process and change in volume are 500 units, 400 units, and 2 units. What is the pressure that is exerted on the gas during this process?
- a)20 units
- b)80 units
- c)100 units
- d)50 units
Correct answer is option 'D'. Can you explain this answer?
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The enthalpy, internal energy during a process and change in volume ar...
Enthalpy and Internal Energy Relationship
-----------------------------------------
Enthalpy is a thermodynamic property that represents the total heat content of a system, while internal energy represents the total energy stored within the system. The relationship between enthalpy (H) and internal energy (U) is given by the equation:
H = U + PV
where P is the pressure and V is the volume of the system.
Given information:
----------------
Enthalpy (H) = 500 units
Internal Energy (U) = 400 units
Change in Volume (ΔV) = 2 units
To find the pressure exerted on the gas during this process, we can rearrange the equation for enthalpy to solve for pressure:
P = (H - U) / V
Calculating the Pressure:
-------------------------
Substituting the given values into the equation, we have:
P = (500 - 400) / 2
P = 100 / 2
P = 50 units
Therefore, the pressure exerted on the gas during this process is 50 units.
Final Answer:
-------------
The correct answer is option 'D' - 50 units.
-----------------------------------------
Enthalpy is a thermodynamic property that represents the total heat content of a system, while internal energy represents the total energy stored within the system. The relationship between enthalpy (H) and internal energy (U) is given by the equation:
H = U + PV
where P is the pressure and V is the volume of the system.
Given information:
----------------
Enthalpy (H) = 500 units
Internal Energy (U) = 400 units
Change in Volume (ΔV) = 2 units
To find the pressure exerted on the gas during this process, we can rearrange the equation for enthalpy to solve for pressure:
P = (H - U) / V
Calculating the Pressure:
-------------------------
Substituting the given values into the equation, we have:
P = (500 - 400) / 2
P = 100 / 2
P = 50 units
Therefore, the pressure exerted on the gas during this process is 50 units.
Final Answer:
-------------
The correct answer is option 'D' - 50 units.
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Community Answer
The enthalpy, internal energy during a process and change in volume ar...
We know that ΔH = ΔU + PΔV; ΔH is the enthalpy, ΔU is the internal energy, ΔV is the change in volume and P is the pressure. So by substituting the enthalpy, internal energy during a process and change in volume as 500 units, 400 units and 2 units, we get pressure as 50 units.
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The enthalpy, internal energy during a process and change in volume are 500 units, 400 units, and 2 units. What is the pressure that is exerted on the gas during this process?a)20 unitsb)80 unitsc)100 unitsd)50 unitsCorrect answer is option 'D'. Can you explain this answer?
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The enthalpy, internal energy during a process and change in volume are 500 units, 400 units, and 2 units. What is the pressure that is exerted on the gas during this process?a)20 unitsb)80 unitsc)100 unitsd)50 unitsCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The enthalpy, internal energy during a process and change in volume are 500 units, 400 units, and 2 units. What is the pressure that is exerted on the gas during this process?a)20 unitsb)80 unitsc)100 unitsd)50 unitsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpy, internal energy during a process and change in volume are 500 units, 400 units, and 2 units. What is the pressure that is exerted on the gas during this process?a)20 unitsb)80 unitsc)100 unitsd)50 unitsCorrect answer is option 'D'. Can you explain this answer?.
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