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A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is?
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A conducting rod of length 2l is rotating with constant angular speed ...
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A conducting rod of length 2l is rotating with constant angular speed ...
Introduction:
When a conducting rod rotates in a uniform magnetic field, an electromotive force (emf) is induced between the two ends of the rod. This phenomenon is known as electromagnetic induction and is governed by Faraday's law of electromagnetic induction.
Faraday's Law of Electromagnetic Induction:
Faraday's law states that the emf induced in a closed loop is equal to the rate of change of magnetic flux through the loop. Mathematically, it can be expressed as:
emf = -d(Φ)/dt
Where,
emf is the electromagnetic force induced,
d(Φ) is the change in magnetic flux through the loop,
dt is the change in time.
Magnetic Flux and its Change:
The magnetic flux through a loop is given by the product of the magnetic field strength (B) and the area (A) of the loop. In this case, since the magnetic field is parallel to the axis of rotation, the magnetic flux remains constant.
Therefore, d(Φ)/dt = 0, implying that there is no change in magnetic flux over time.
Induced emf:
Since there is no change in magnetic flux, the induced emf is zero. However, it is important to note that if there were a change in magnetic flux, an emf would be induced.
Conclusion:
In the given scenario, a conducting rod of length 2l rotating with a constant angular speed about its perpendicular bisector in a uniform magnetic field parallel to the axis of rotation will not induce an emf between its ends. This is due to the absence of a change in magnetic flux.
When a conducting rod rotates in a uniform magnetic field, an electromotive force (emf) is induced between the two ends of the rod. This phenomenon is known as electromagnetic induction and is governed by Faraday's law of electromagnetic induction.
Faraday's Law of Electromagnetic Induction:
Faraday's law states that the emf induced in a closed loop is equal to the rate of change of magnetic flux through the loop. Mathematically, it can be expressed as:
emf = -d(Φ)/dt
Where,
emf is the electromagnetic force induced,
d(Φ) is the change in magnetic flux through the loop,
dt is the change in time.
Magnetic Flux and its Change:
The magnetic flux through a loop is given by the product of the magnetic field strength (B) and the area (A) of the loop. In this case, since the magnetic field is parallel to the axis of rotation, the magnetic flux remains constant.
Therefore, d(Φ)/dt = 0, implying that there is no change in magnetic flux over time.
Induced emf:
Since there is no change in magnetic flux, the induced emf is zero. However, it is important to note that if there were a change in magnetic flux, an emf would be induced.
Conclusion:
In the given scenario, a conducting rod of length 2l rotating with a constant angular speed about its perpendicular bisector in a uniform magnetic field parallel to the axis of rotation will not induce an emf between its ends. This is due to the absence of a change in magnetic flux.
Community Answer
A conducting rod of length 2l is rotating with constant angular speed ...
[B×omega×(r)^2]÷2
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A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is?
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A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is?.
A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conducting rod of length 2l is rotating with constant angular speed omega about its perpendicular bisector.A uniform magnetic field exist paraller to the axis of rotation.The emf induced btw two ends of the rod is?.
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