NEET Exam > NEET Questions > Aconducting rod of 1m length rotating with a ...
Start Learning for Free
Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?
1. 1V 2. 2V 3. 0.5V 4. 0.25V?
1. 1V 2. 2V 3. 0.5V 4. 0.25V?
Most Upvoted Answer
Aconducting rod of 1m length rotating with a frequency of 50rev/sec ab...
Given:
- Length of the conducting rod, L = 1 m
- Frequency of rotation, f = 50 rev/sec
- Magnetic field, B = 6.28 mT = 6.28 × 10⁻³ T
To Find:
The value of induced emf between the ends of the rod.
Solution:
1. Calculate the Angular Velocity:
The angular velocity, ω, can be calculated using the formula:
ω = 2πf
Given that f = 50 rev/sec, we can substitute the value:
ω = 2π × 50 = 100π rad/sec
2. Calculate the Magnetic Flux:
The magnetic flux, Φ, can be calculated using the formula:
Φ = B × A
Where A is the area of the loop. In this case, the area is given by the product of the length of the rod and the width of the rod.
Given that the length of the rod, L = 1 m, we can assume that the width of the rod is negligible.
Therefore, the area, A = L × w = 1 × 0 = 0 m²
Since the area is zero, the magnetic flux, Φ, will also be zero.
3. Calculate the Induced emf:
The induced emf, ε, can be calculated using the formula:
ε = -N dΦ/dt
Where N is the number of turns in the coil and dΦ/dt is the rate of change of magnetic flux.
In this case, the rod is rotating about its end, so the number of turns, N = 1.
Since the magnetic flux, Φ, is zero, the rate of change of magnetic flux, dΦ/dt, will also be zero.
Therefore, the induced emf, ε, will be zero.
Answer:
The value of the induced emf between the ends of the rod is 0V. (Option 3)
- Length of the conducting rod, L = 1 m
- Frequency of rotation, f = 50 rev/sec
- Magnetic field, B = 6.28 mT = 6.28 × 10⁻³ T
To Find:
The value of induced emf between the ends of the rod.
Solution:
1. Calculate the Angular Velocity:
The angular velocity, ω, can be calculated using the formula:
ω = 2πf
Given that f = 50 rev/sec, we can substitute the value:
ω = 2π × 50 = 100π rad/sec
2. Calculate the Magnetic Flux:
The magnetic flux, Φ, can be calculated using the formula:
Φ = B × A
Where A is the area of the loop. In this case, the area is given by the product of the length of the rod and the width of the rod.
Given that the length of the rod, L = 1 m, we can assume that the width of the rod is negligible.
Therefore, the area, A = L × w = 1 × 0 = 0 m²
Since the area is zero, the magnetic flux, Φ, will also be zero.
3. Calculate the Induced emf:
The induced emf, ε, can be calculated using the formula:
ε = -N dΦ/dt
Where N is the number of turns in the coil and dΦ/dt is the rate of change of magnetic flux.
In this case, the rod is rotating about its end, so the number of turns, N = 1.
Since the magnetic flux, Φ, is zero, the rate of change of magnetic flux, dΦ/dt, will also be zero.
Therefore, the induced emf, ε, will be zero.
Answer:
The value of the induced emf between the ends of the rod is 0V. (Option 3)
Community Answer
Aconducting rod of 1m length rotating with a frequency of 50rev/sec ab...
.157 volt ( e= Bwl^2/2)
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?
Question Description
Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?.
Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?.
Solutions for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? defined & explained in the simplest way possible. Besides giving the explanation of
Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V?, a detailed solution for Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? has been provided alongside types of Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? theory, EduRev gives you an
ample number of questions to practice Aconducting rod of 1m length rotating with a frequency of 50rev/sec about its one of end inside the uniform magnetic field od 6.28mT.The value of induced emf between end od rod is?1. 1V 2. 2V 3. 0.5V 4. 0.25V? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup