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A particle is projected from origin with velocity (4i+9j) .the acceleration in the region is constant and-10j the magnitude of velocity after one second is.?
Most Upvoted Answer
A particle is projected from origin with velocity (4i+9j) .the acceler...
Given:
- Initial velocity of the particle, v0 = 4i + 9j
- Constant acceleration, a = -10j

To find:
- Magnitude of velocity after one second

Approach:
To find the magnitude of velocity after one second, we can use the equations of motion.

Equations of motion:
1. v = u + at
2. v2 = u2 + 2as

Solution:
1. Calculating the velocity after one second using equation 1:
Initial velocity, u = 4i + 9j
Acceleration, a = -10j
Time, t = 1 second

Using equation 1: v = u + at
v = (4i + 9j) + (-10j)
v = 4i - j

2. Finding the magnitude of velocity after one second:
The magnitude of a vector is given by the formula: |v| = √(vx2 + vy2)

Given v = 4i - j
vx = 4
vy = -1

Using the magnitude formula: |v| = √(42 + (-1)2)
|v| = √(16 + 1)
|v| = √17

Therefore, the magnitude of velocity after one second is √17.

Summary:
The magnitude of velocity after one second for a particle projected from the origin with initial velocity (4i + 9j) and constant acceleration (-10j) is √17.
Community Answer
A particle is projected from origin with velocity (4i+9j) .the acceler...
Use v=u + at whr we need to find v and time t=1 'u' is given 4i+9j nd a=-10 j...substitute in the equation...v= (4i+9j)-(10j)(1)..v= 4i-1j...
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A particle is projected from origin with velocity (4i+9j) .the acceleration in the region is constant and-10j the magnitude of velocity after one second is.?
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