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2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution?
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2bromopentane is treated wid alc. kOH sol. what will be the major prod...
Dehydrohalogenation takes place forming pent2 ene the hydrogen lost is from beta position hence beta elimination
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2bromopentane is treated wid alc. kOH sol. what will be the major prod...
B) option
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Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. Nucleophilic substitution will be fastest in case of

Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in case of

Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in which of the following solvents?

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2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution?
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2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution?.
Solutions for 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? defined & explained in the simplest way possible. Besides giving the explanation of 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution?, a detailed solution for 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? has been provided alongside types of 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? theory, EduRev gives you an ample number of questions to practice 2bromopentane is treated wid alc. kOH sol. what will be the major product formed in this reaction and what type of elimination called ? a) Pent-1-ene;beta elimination b)pent-2-ene;beta elimination c) Pent-1-ene; nucleophilic substitution d) Pent-2-ene; nucleophilic substitution? tests, examples and also practice NEET tests.
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