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For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )?
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For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(...
It will become 16 times as volume is inversely proportional to concentration so when volume. become 1/4 times so concentration will become 4 times the initial concentration. and as acc to equation (A)^2 so rate will become 4^2 ie 16 times..Hope this will help
Community Answer
For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(...
Explanation:
Given, the reaction between gaseous compounds, 2A + B = C + D, the reaction rate is given by k(A)(B).
When the volume of the container is reduced to 1/4th of the initial volume, the concentration of the reactants will increase by 4 times, as the number of molecules in the same volume will increase.
Hence, the rate of reaction will also increase proportionally to the concentration of the reactants. Using the initial rate as a reference, we can calculate the new rate of the reaction as follows:
Calculation:
Let the initial rate of reaction be R_1.
When the volume of the container is reduced to 1/4th, the concentration of A and B will become 4 times the initial concentration. Therefore, the new rate of reaction R_2 will be:
R_2 = k(4A)(4B) = 16k(A)(B)
Thus, the new rate of reaction is 16 times the initial rate of reaction.
Conclusion:
Therefore, the rate of reaction will increase 16 times when the volume of the container is reduced to 1/4th of the initial volume.
Given, the reaction between gaseous compounds, 2A + B = C + D, the reaction rate is given by k(A)(B).
When the volume of the container is reduced to 1/4th of the initial volume, the concentration of the reactants will increase by 4 times, as the number of molecules in the same volume will increase.
Hence, the rate of reaction will also increase proportionally to the concentration of the reactants. Using the initial rate as a reference, we can calculate the new rate of the reaction as follows:
Calculation:
Let the initial rate of reaction be R_1.
When the volume of the container is reduced to 1/4th, the concentration of A and B will become 4 times the initial concentration. Therefore, the new rate of reaction R_2 will be:
R_2 = k(4A)(4B) = 16k(A)(B)
Thus, the new rate of reaction is 16 times the initial rate of reaction.
Conclusion:
Therefore, the rate of reaction will increase 16 times when the volume of the container is reduced to 1/4th of the initial volume.
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For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )?
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For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )?.
For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a reaction between gaseous compounds,2A+B=C+D the reaction rate=k(A)(B).If the volume of container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate ? (options: 16times , 4times , 1/8times, 1/16 times )?.
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