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The displacement of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = square root of x + 3, where x is in metre and t is in second.t he work done by the force in first 6 sec is. A.18 B.0 C.9/2 D.36?
Most Upvoted Answer
The displacement of a particle moving in one dimension under the actio...
I think answer is (B) 0...bcz the solution is; t=√x + 3 it can be written as √x=t-3 (case 1) squaring on both sides in case 1 we get; x=t square +9-6t. (case 2) if V be the velocity of the particle; v=dx÷dt=d÷dt× X v=d÷dt(t square+9-6t) v=2t-6 when V=0 2t-6=0 therefore t=3sec (case 3) substitute case 3 in case 2 we get x= 3 square +9-6×3 x=18-18 therefore X=0...hope u may be clear...
Community Answer
The displacement of a particle moving in one dimension under the actio...
Suriya krishnan why did u take V=0 ??
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The displacement of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = square root of x + 3, where x is in metre and t is in second.t he work done by the force in first 6 sec is. A.18 B.0 C.9/2 D.36?
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The displacement of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = square root of x + 3, where x is in metre and t is in second.t he work done by the force in first 6 sec is. A.18 B.0 C.9/2 D.36? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The displacement of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = square root of x + 3, where x is in metre and t is in second.t he work done by the force in first 6 sec is. A.18 B.0 C.9/2 D.36? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The displacement of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = square root of x + 3, where x is in metre and t is in second.t he work done by the force in first 6 sec is. A.18 B.0 C.9/2 D.36?.
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