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Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be? (please give full working, I'm not able to balance the eqn)?
Verified Answer
Number of moles of MnO4- required to oxidise one mole of ferrous oxala...
The balanced chemical reaction is : 3 MnO4{-} + 24 H{+} + 5 FeC2O4 → 3 Mn{2+} + 12 H2O + 10 CO2 + 5 Fe{3+} Since, 5 moles of FeC2O4 reacts with 3 moles of KMnO4 , therefore, 1 mole of FeC2O4 will require 3/5 mole of KMnO4.
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Number of moles of MnO4- required to oxidise one mole of ferrous oxala...
Pls can you explain how you balanced the eqn?
Community Answer
Number of moles of MnO4- required to oxidise one mole of ferrous oxala...
3/ 5 moles...
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Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be? (please give full working, I'm not able to balance the eqn)?
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Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be? (please give full working, I'm not able to balance the eqn)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be? (please give full working, I'm not able to balance the eqn)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be? (please give full working, I'm not able to balance the eqn)?.
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