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In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)?
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In an experiment it showed that 10 mL of 0.05M solution of chloride re...
Experiment Details:
- Volume of chloride solution used: 10 mL
- Concentration of chloride solution: 0.05M
- Volume of AgNO3 solution required: 10 mL
- Concentration of AgNO3 solution: 0.1M
Molarity Calculation:
Molarity (M) is defined as the number of moles of solute per liter of solution. To determine the moles of chloride and AgNO3, we can use the formula:
Moles = Molarity × Volume (in liters)
Moles of Chloride:
Moles of chloride = 0.05M × 0.01L = 0.0005 moles
Moles of AgNO3:
Moles of AgNO3 = 0.1M × 0.01L = 0.001 moles
Stoichiometry:
AgNO3 + XCl → AgCl + XNO3
The balanced equation shows that 1 mole of AgNO3 reacts with 1 mole of chloride to form 1 mole of AgCl. Therefore, the ratio of moles of AgNO3 to moles of chloride is 1:1.
In the experiment, 0.001 moles of AgNO3 reacted with 0.0005 moles of chloride. This means that the moles of AgNO3 and chloride are in a 1:2 ratio.
Formula of Chloride:
The formula of chloride can be determined by considering the valency of the other element (X).
Since the moles of AgNO3 and chloride are in a 1:2 ratio, we can conclude that the valency of chloride is 1.
The formula of chloride should be XCl1. However, the valency of chlorine is also 1, so the formula simplifies to XCl.
Therefore, the formula of the chloride is XCl.
Explanation:
In the given experiment, the volume and concentration of the chloride solution and AgNO3 solution were provided. By calculating the moles of chloride and AgNO3, we determined the ratio of moles between these two substances. Based on the stoichiometry of the balanced equation, we concluded that the moles of AgNO3 and chloride are in a 1:2 ratio. Since the valency of chlorine is 1, the formula of the chloride is XCl.
- Volume of chloride solution used: 10 mL
- Concentration of chloride solution: 0.05M
- Volume of AgNO3 solution required: 10 mL
- Concentration of AgNO3 solution: 0.1M
Molarity Calculation:
Molarity (M) is defined as the number of moles of solute per liter of solution. To determine the moles of chloride and AgNO3, we can use the formula:
Moles = Molarity × Volume (in liters)
Moles of Chloride:
Moles of chloride = 0.05M × 0.01L = 0.0005 moles
Moles of AgNO3:
Moles of AgNO3 = 0.1M × 0.01L = 0.001 moles
Stoichiometry:
AgNO3 + XCl → AgCl + XNO3
The balanced equation shows that 1 mole of AgNO3 reacts with 1 mole of chloride to form 1 mole of AgCl. Therefore, the ratio of moles of AgNO3 to moles of chloride is 1:1.
In the experiment, 0.001 moles of AgNO3 reacted with 0.0005 moles of chloride. This means that the moles of AgNO3 and chloride are in a 1:2 ratio.
Formula of Chloride:
The formula of chloride can be determined by considering the valency of the other element (X).
Since the moles of AgNO3 and chloride are in a 1:2 ratio, we can conclude that the valency of chloride is 1.
The formula of chloride should be XCl1. However, the valency of chlorine is also 1, so the formula simplifies to XCl.
Therefore, the formula of the chloride is XCl.
Explanation:
In the given experiment, the volume and concentration of the chloride solution and AgNO3 solution were provided. By calculating the moles of chloride and AgNO3, we determined the ratio of moles between these two substances. Based on the stoichiometry of the balanced equation, we concluded that the moles of AgNO3 and chloride are in a 1:2 ratio. Since the valency of chlorine is 1, the formula of the chloride is XCl.
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In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)?
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In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)?.
In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment it showed that 10 mL of 0.05M solution of chloride required 10 mL of 0.1M solution of AgNO3 which of the following will be the formula of the chloride (X stands for the symbol of the ele- ment other than chlorine)?.
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