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In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.?
Most Upvoted Answer
In an experiment it showed that 10 ml of 0.05 M solution of chloride r...
Basically this question is asking about the valency factor of Cl
mili equivalents for Cl=mili mole×V.f=10×0.05V.f=0.5V.f
mili equivalents of AgNO3=10×0.1×V.f=1(V. f=1)
so,
0.5×V.f=1
V. f=2
hence XCl2
option B
mili equivalents for Cl=mili mole×V.f=10×0.05V.f=0.5V.f
mili equivalents of AgNO3=10×0.1×V.f=1(V. f=1)
so,
0.5×V.f=1
V. f=2
hence XCl2
option B
Community Answer
In an experiment it showed that 10 ml of 0.05 M solution of chloride r...
Title: Explanation for the formula of chloride
Heading 1: Given information
- 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3.
Heading 2: Concept of the experiment
- The experiment involves a precipitation reaction between chloride ions and silver ions.
- The reaction forms a white precipitate of silver chloride (AgCl).
Heading 3: Balanced chemical equation for the reaction
- AgNO3 + NaCl → AgCl + NaNO3
Heading 4: Calculation of moles
- Using the formula: moles = concentration x volume (in liters)
- Moles of chloride ions = 0.05 x 0.01 = 0.0005 moles
- Moles of silver ions = 0.1 x 0.01 = 0.001 moles
Heading 5: Determination of the formula of chloride
- The ratio of chloride to silver ions in the reaction is 1:1 (from the balanced chemical equation).
- Therefore, the moles of chloride ions is equal to the moles of silver ions.
- The formula of chloride can be determined by dividing the moles of chloride ions by the volume (in liters) of the solution used in the experiment.
- Formula of chloride = moles of chloride ions / volume of chloride solution used
- Formula of chloride = 0.0005 / 0.01 = 0.05 moles per liter
- The formula of chloride is XCl2, where X represents the symbol of the element other than chloride.
Heading 6: Conclusion
- The formula of chloride determined from the experiment is XCl2.
Heading 1: Given information
- 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3.
Heading 2: Concept of the experiment
- The experiment involves a precipitation reaction between chloride ions and silver ions.
- The reaction forms a white precipitate of silver chloride (AgCl).
Heading 3: Balanced chemical equation for the reaction
- AgNO3 + NaCl → AgCl + NaNO3
Heading 4: Calculation of moles
- Using the formula: moles = concentration x volume (in liters)
- Moles of chloride ions = 0.05 x 0.01 = 0.0005 moles
- Moles of silver ions = 0.1 x 0.01 = 0.001 moles
Heading 5: Determination of the formula of chloride
- The ratio of chloride to silver ions in the reaction is 1:1 (from the balanced chemical equation).
- Therefore, the moles of chloride ions is equal to the moles of silver ions.
- The formula of chloride can be determined by dividing the moles of chloride ions by the volume (in liters) of the solution used in the experiment.
- Formula of chloride = moles of chloride ions / volume of chloride solution used
- Formula of chloride = 0.0005 / 0.01 = 0.05 moles per liter
- The formula of chloride is XCl2, where X represents the symbol of the element other than chloride.
Heading 6: Conclusion
- The formula of chloride determined from the experiment is XCl2.
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In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.?
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In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.?.
In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.?.
Solutions for In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? in English & in Hindi are available as part of our courses for NEET.
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In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.?, a detailed solution for In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? has been provided alongside types of In an experiment it showed that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO3, then which of the following will be the formula of the chloride ( x stands for the symbol of the element other than chloride) A)X2Cl2 B)XCl2 C)XCl4 D)X2Cl The correct answer is XCl2. plz explain.? theory, EduRev gives you an
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