The same quantity of electricity is passed through two electrolytic ce...
If u pass 2 mole of electron(2e-) in nacl ..... then one mole of Cl2 produce whereas ...in dil.H2SO4 you have to pass 4 mole of electrons(4e-)....to produce one mole of O2therefore in 4e- ...2 mole Cl2 and 1 mole O2 produce2:1
The same quantity of electricity is passed through two electrolytic ce...
Explanation:
Electrolysis of NaCl:
- In the electrolysis of NaCl, at the anode, Cl2 gas is evolved.
- The reaction at the anode is: 2Cl- → Cl2 + 2e-
- Therefore, 1 mole of Cl2 is evolved per 2 moles of electrons.
Electrolysis of H2SO4:
- In the electrolysis of Dil H2SO4, at the anode, O2 gas is evolved.
- The reaction at the anode is: 4OH- → O2 + 2H2O + 4e-
- Therefore, 1 mole of O2 is evolved per 4 moles of electrons.
Comparison:
- For NaCl electrolysis: 1 mole of Cl2 is evolved per 2 moles of electrons.
- For H2SO4 electrolysis: 1 mole of O2 is evolved per 4 moles of electrons.
Volume of Cl2 and O2 evolved:
- When the same quantity of electricity is passed through both cells, the number of moles of electrons passing through each cell is the same.
- Since 1 mole of Cl2 is evolved per 2 moles of electrons in the NaCl cell, and 1 mole of O2 is evolved per 4 moles of electrons in the H2SO4 cell, the volume ratio of Cl2 to O2 evolved is 1:2.
Conclusion:
- Therefore, the correct answer is option b) 1:2, as the volume of Cl2 and O2 evolved at the anode under the same conditions of temperature and pressure is in the ratio of 1:2.
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