200ml N/10 h2so4 is mixed with 300 my N/100 NaoH. what's its normality?

Question

Answer

Calculation of Normality of Solution

Given:

Volume of N/10 H2SO4 = 200mL

Volume of N/100 NaOH = 300mL

Step 1: Calculate the number of moles of H2SO4 and NaOH

Molarity of N/10 H2SO4 = 1/10 = 0.1M

Moles of H2SO4 = Molarity x Volume (in liters) = 0.1 x 0.2 = 0.02 moles

Molarity of N/100 NaOH = 1/100 = 0.01M

Moles of NaOH = Molarity x Volume (in liters) = 0.01 x 0.3 = 0.003 moles

Step 2: Determine the limiting reagent

H2SO4 is the limiting reagent because it has fewer moles than NaOH

Step 3: Calculate the number of moles of excess NaOH

Excess NaOH = Moles of NaOH - Moles of H2SO4 = 0.003 - 0.02 = -0.017 moles

Step 4: Calculate the normality of the solution

Normality of the solution = (Moles of H2SO4 / Volume of solution in liters) x 1000

Volume of solution = Volume of H2SO4 + Volume of NaOH = 0.2L + 0.3L = 0.5L

Normality of the solution = (0.02 / 0.5) x 1000 = 40 N

Final Answer: The normality of the solution is 40 N.

Explanation: The given problem involves the mixing of a solution of N/10 H2SO4 with a solution of N/100 NaOH. The number of moles of each of the solutions is calculated using the formula Moles = Molarity x Volume (in liters). The limiting reagent is then determined by comparing the number of moles of each of the reactants. In this case, H2SO4 is the limiting reagent because it has fewer moles than NaOH. The number of moles of excess NaOH is then calculated by subtracting the moles of H2SO4 from the moles of NaOH. The normality of the solution is then calculated using the formula Normality = (Moles of H2SO4 / Volume of solution in liters) x 1000. Finally, the normality of the solution is calculated to be 40 N.

Answer

Use N1V1 + N2V2= N Vtotal.. here as one is giving H+ nd one OH-, so we will use 200*1/10-300*1/100=N*300, N=0.034

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