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A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .?
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A tube of sugar solution 20cm long is placed between crossed Nicols of...
Problem: A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5. If optical rotation is 13 degrees and specific rotation us 65 degrees then determine the strength of the solution.
Solution:
To solve this problem, we need to understand some basic concepts related to polarization of light and optical activity.
Optical Activity:
Optical activity is the ability of a substance to rotate the plane of polarization of plane-polarized light. It is measured by the angle of rotation (α) produced when a polarized plane of light passes through a sample of known length (l) at a specific wavelength.
Specific Rotation:
Specific rotation is defined as the angle of rotation (α) produced by one gram of a substance per unit length (l) of the sample at a specific wavelength. It is expressed in degrees per centimeter per gram (°/cm/g).
Now, let's solve the given problem step by step:
Step 1:
Given, the length of the tube (l) = 20 cm, angle of rotation (α) = 13 degrees, and specific rotation ([α]D) = 65 degrees.
Step 2:
We know that the angle of rotation (α) is directly proportional to the concentration (c) of the solution. Mathematically, it can be represented as:
α = [α]D × l × c
Where,
α = angle of rotation
[α]D = specific rotation
l = length of the tube
c = concentration of the solution
Step 3:
Substituting the given values, we get:
13 = 65 × 20 × c
Simplifying, we get:
c = 0.1 g/cc
Therefore, the strength of the solution is 0.1 g/cc.
Solution:
To solve this problem, we need to understand some basic concepts related to polarization of light and optical activity.
Optical Activity:
Optical activity is the ability of a substance to rotate the plane of polarization of plane-polarized light. It is measured by the angle of rotation (α) produced when a polarized plane of light passes through a sample of known length (l) at a specific wavelength.
Specific Rotation:
Specific rotation is defined as the angle of rotation (α) produced by one gram of a substance per unit length (l) of the sample at a specific wavelength. It is expressed in degrees per centimeter per gram (°/cm/g).
Now, let's solve the given problem step by step:
Step 1:
Given, the length of the tube (l) = 20 cm, angle of rotation (α) = 13 degrees, and specific rotation ([α]D) = 65 degrees.
Step 2:
We know that the angle of rotation (α) is directly proportional to the concentration (c) of the solution. Mathematically, it can be represented as:
α = [α]D × l × c
Where,
α = angle of rotation
[α]D = specific rotation
l = length of the tube
c = concentration of the solution
Step 3:
Substituting the given values, we get:
13 = 65 × 20 × c
Simplifying, we get:
c = 0.1 g/cc
Therefore, the strength of the solution is 0.1 g/cc.
Community Answer
A tube of sugar solution 20cm long is placed between crossed Nicols of...
Use this formula alpa =theta /L *C in this alpa is specific rotation and theta optical rotation L is lenght we have to calculate C(concentration) so 65=13*100/20*C we get C=1kg/L change in that unit
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A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .?
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A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .?.
A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tube of sugar solution 20cm long is placed between crossed Nicols of wavelengths 6×10-5 .If optical rotation is 13 degree and specific rotation us 65 degree then determine strength of solution It's answer is 0.1 g/cc please explain this question with solution. .?.
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