Without adding, find the sum. 1 + 3 + 5 + 7 + 9 + 11 + 13a)36b)49c)25d...
Total consecutive odd numbers (n) = 7
We know that, Sum = n2
= 72
= 49
Hence, the correct answer is 49
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Without adding, find the sum. 1 + 3 + 5 + 7 + 9 + 11 + 13a)36b)49c)25d...
We have to just add that how many odd no. are ther
e then we have to take out
Without adding, find the sum. 1 + 3 + 5 + 7 + 9 + 11 + 13a)36b)49c)25d...
The given sequence is 1, 3, 5, 7, 9, 11, 13. We are required to find the sum of these numbers without actually adding them.
Here's how we can approach this problem:
Identifying the pattern:
- By observing the given sequence, we can see that it consists of odd numbers starting from 1.
- Each number in the sequence is obtained by adding 2 to the previous number.
Using the formula for the sum of an arithmetic series:
- An arithmetic series is a sequence of numbers in which the difference between any two consecutive terms is constant.
- The sum of an arithmetic series can be found using the formula: S = (n/2)(a + l), where S is the sum of the series, n is the number of terms, a is the first term, and l is the last term.
- In this case, the first term (a) is 1, the common difference (d) is 2, and the last term (l) is 13.
Calculating the number of terms:
- To find the number of terms (n) in the sequence, we can use the formula: n = (l - a)/d + 1.
- Substituting the values, we get: n = (13 - 1)/2 + 1 = 6.
Calculating the sum:
- Now that we have the number of terms (n) and the first term (a), we can calculate the sum using the formula: S = (n/2)(a + l).
- Substituting the values, we get: S = (6/2)(1 + 13) = 3 * 14 = 42.
Therefore, the sum of the given sequence 1, 3, 5, 7, 9, 11, 13 is 42.
Since none of the given options match the calculated sum of 42, it seems that there might be an error in the options provided.