Two similar and equal charges repel each other with force of 1.6N ,whe...
Problem: Two similar and equal charges repel each other with force of 1.6N, when placed 3m apart. Strength of each charge is:
Solution:
Given:
Force between the two charges, F = 1.6N
Distance between the two charges, r = 3m
Formula:
The force between two point charges is given by Coulomb's law:
F = (1/4πε0) × (q1 q2) / r2
where, ε0 is the permittivity of free space, q1 and q2 are the two charges and r is the distance between them.
Calculation:
Let the strength of each charge be q.
Then, from Coulomb's law,
1.6 = (1/4πε0) × q2 / (3)2
Using the value of ε0 = 8.85 × 10-12 F/m,
q2 = (1.6 × 9 × 108) / (4 × π × 8.85 × 10-12)
q2 = 4.52 × 10-6
q = ± 2μC
Therefore, the strength of each charge is 2μC.
Explanation:
- Coulomb's law is used to calculate the force between two point charges.
- The equation uses the distance between the charges and the strength of the charges as inputs.
- In this problem, the force and distance are given, and the equation is used to find the strength of each charge.
- The value of ε0 is a constant that is used to relate the electric force to the charges creating the force.
- The calculated value of q is ± 2μC because the equation only gives the magnitude of the charge, and the sign must be determined from the fact that the charges are similar and repel each other.
Two similar and equal charges repel each other with force of 1.6N ,whe...
Answer is option A as F=(kq^2) /r2Substitute the values of r, F and K=9x10^9Then we get q=4x10^5To convert into mu 1mu=10^-610 is multipled in both denominator and numerator 40x 10^-6=40mu
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