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Can you explain the answer of this question below:
Two metallic oxides contain 27.6% and 30.0% oxygen respectively. If the formula of the first oxide is  M3O4, that of the second will be
  • A:
    MO2
  • B:
    M2O3
  • C:
    M2O5
  • D:
    MO
The answer is d.
Verified Answer
Can you explain the answer of this question below:Two metallic oxides ...
Given that, formula of first oxide = M3O4
Let mass of the metal = x
% of metal in M3O4 = (3x/ 3x+64) *100
but as given % age = (100-27.6) = 72.4 %
so, (3x/ 3x+64)*100 = 72.4
or x = 56.
in 2nd oxide,
oxygen = 30%....so metal = 70%
so, the ratio is
M : O
70/56 : 30/16
1.25 : 1.875
2 : 3
so, 2nd oxide is M2O3

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Most Upvoted Answer
Can you explain the answer of this question below:Two metallic oxides ...
1st metallic oxide ,m = 72.4% ,o =27.6% ,let metal's atomic mass = x .m:o = 72.6/x : 27.6/16 = 3:4 == x=55.96 ,2nd metallic oxide , m=70 % ,o =30% , m:o =70/55.96 : 30/16 =2:3. 2nd metallic oxide 's formula = M2 O3 ( b )
Community Answer
Can you explain the answer of this question below:Two metallic oxides ...
Answer is option B
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Can you explain the answer of this question below:Two metallic oxides contain 27.6% and 30.0%oxygen respectively. If the formula of the first oxideisM3O4,that of the second will beA:MO2B:M2O3C:M2O5D:MOThe answer is d.
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