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In the following gaseous phase first order reaction A -> 2B+C Initial pressure was observed to be 200 mmHg and after 20 minutes, it changed to 400mmHg. The rate constant for the reaction is?
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In the following gaseous phase first order reaction A -> 2B+C Initial ...


Calculation of Rate Constant for First Order Reaction

The rate of a first order reaction is given by the rate law:

rate = k[A]

where A is the concentration of the reactant A, k is the rate constant, and the order of the reaction is 1.

Given Data

- Initial pressure (P₀) = 200 mmHg
- Final pressure (P) = 400 mmHg
- Time (t) = 20 minutes

Calculation of Concentration of A

Since the reaction is A -> 2B + C, the decrease in the pressure of A is directly proportional to the decrease in concentration of A. Therefore, the concentration of A at time t can be calculated as:

[A] = P₀ - P = 200 - 400 = -200 mmHg

Calculation of Rate Constant (k)

To calculate the rate constant k, we can use the integrated rate law for first-order reactions:

ln([A]₀/[A]) = kt

Substitute the values:

ln(200/-200) = k(20 minutes)

k = -0.693/20 = -0.03465 min⁻¹

Therefore, the rate constant for the given reaction is 0.03465 min⁻¹.
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In the following gaseous phase first order reaction A -> 2B+C Initial pressure was observed to be 200 mmHg and after 20 minutes, it changed to 400mmHg. The rate constant for the reaction is?
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