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You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this job
- a)4
- b)10
- c)8
- d)20
Correct answer is 'C'. Can you explain this answer?
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Verified Answer
You are given several identical resistances each of value R=10 Ω and e...
To carry a current of 4 amperes, we need four paths, each carrying a current of one ampere. Let r be the resistance of each path. These are connected in parallel. Hence, their equivalent resistance will be r/4. According to the given problem
r/4=5
r=20
For this propose two resistances should be connected. There are four such combinations. Hence, the total number of resistance = 4 * 2 =8
Most Upvoted Answer
You are given several identical resistances each of value R=10 Ω and e...
Understanding the problem:
To create a resistance of 5Ω that can carry a current of 4 amperes, we need to determine the minimum number of 10Ω resistors that can be combined to achieve this.
Calculating the equivalent resistance:
- To find the total resistance, we can use the formula for resistors in parallel: 1/Req = 1/R1 + 1/R2 + 1/R3 + ...
- Given that each resistor has a value of 10Ω, we can substitute this into the formula: 1/Req = 1/10 + 1/10 + 1/10 + 1/10 = 4/10
- Simplifying, we get: 1/Req = 0.4, which means Req = 1/0.4 = 2.5Ω
Determining the number of resistors needed:
- Since we are using 10Ω resistors, we must calculate how many of these resistors are needed to achieve an equivalent resistance of 2.5Ω.
- To do this, we divide the desired resistance by the resistance of each individual resistor: 2.5/10 = 0.25
- Therefore, we need 0.25 or 1/0.25 = 4 resistors to achieve the desired equivalent resistance.
Conclusion:
Hence, the minimum number of resistors of 10Ω required to create an equivalent resistance of 2.5Ω is 4. Therefore, the correct answer is option (c) 8 resistors.
To create a resistance of 5Ω that can carry a current of 4 amperes, we need to determine the minimum number of 10Ω resistors that can be combined to achieve this.
Calculating the equivalent resistance:
- To find the total resistance, we can use the formula for resistors in parallel: 1/Req = 1/R1 + 1/R2 + 1/R3 + ...
- Given that each resistor has a value of 10Ω, we can substitute this into the formula: 1/Req = 1/10 + 1/10 + 1/10 + 1/10 = 4/10
- Simplifying, we get: 1/Req = 0.4, which means Req = 1/0.4 = 2.5Ω
Determining the number of resistors needed:
- Since we are using 10Ω resistors, we must calculate how many of these resistors are needed to achieve an equivalent resistance of 2.5Ω.
- To do this, we divide the desired resistance by the resistance of each individual resistor: 2.5/10 = 0.25
- Therefore, we need 0.25 or 1/0.25 = 4 resistors to achieve the desired equivalent resistance.
Conclusion:
Hence, the minimum number of resistors of 10Ω required to create an equivalent resistance of 2.5Ω is 4. Therefore, the correct answer is option (c) 8 resistors.
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Community Answer
You are given several identical resistances each of value R=10 Ω and e...
Solution:
To find the minimum number of resistances required, we need to consider the formula for combining resistances in parallel and in series.
Formula for resistances in series:
When resistances are connected in series, the total resistance is the sum of individual resistances.
R_total = R1 + R2 + R3 + ... + Rn
Formula for resistances in parallel:
When resistances are connected in parallel, the reciprocal of the total resistance is the sum of reciprocals of individual resistances.
1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
Given that we have identical resistances of value R = 10 Ω, we can use these formulas to find the minimum number of resistances required.
Step 1: Calculate the total resistance required using the formula for resistances in parallel.
1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
1/5 Ω = 1/10 Ω + 1/10 Ω + 1/10 Ω + ... + 1/10 Ω
1/5 Ω = n/10 Ω
n = 2
Step 2: Calculate the total current required using the formula for resistances in series.
I_total = I1 + I2 + I3 + ... + In
4 A = 1 A + 1 A + 1 A + 1 A
4 A = n A
n = 4
Therefore, the minimum number of resistances required is 4 (Option A).
To find the minimum number of resistances required, we need to consider the formula for combining resistances in parallel and in series.
Formula for resistances in series:
When resistances are connected in series, the total resistance is the sum of individual resistances.
R_total = R1 + R2 + R3 + ... + Rn
Formula for resistances in parallel:
When resistances are connected in parallel, the reciprocal of the total resistance is the sum of reciprocals of individual resistances.
1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
Given that we have identical resistances of value R = 10 Ω, we can use these formulas to find the minimum number of resistances required.
Step 1: Calculate the total resistance required using the formula for resistances in parallel.
1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
1/5 Ω = 1/10 Ω + 1/10 Ω + 1/10 Ω + ... + 1/10 Ω
1/5 Ω = n/10 Ω
n = 2
Step 2: Calculate the total current required using the formula for resistances in series.
I_total = I1 + I2 + I3 + ... + In
4 A = 1 A + 1 A + 1 A + 1 A
4 A = n A
n = 4
Therefore, the minimum number of resistances required is 4 (Option A).
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You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer?
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You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer?.
You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer?.
Solutions for You are given several identical resistances each of value R=10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this joba) 4 b) 10 c) 8 d) 20 Correct answer is 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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