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A 6 V battery is connected to the terminals of a 3 m long wire of uniform thickness and of resistance 100 Ω. The potential difference between two points on the wire, separated by a distance of 50 cm will be
  • a)
    1.5 V
  • b)
    2 V
  • c)
    3 V
  • d)
    1 V
Correct answer is option 'D'. Can you explain this answer?
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- **Given Data:**
- Battery voltage (V) = 6 V
- Length of wire (L) = 3 m
- Resistance of wire (R) = 100 ohms
- Distance between points (d) = 50 cm = 0.5 m
- **Calculating Current Flow:**
- Using Ohm's Law: V = IR
- Current (I) = V / R
- Current (I) = 6 V / 100 ohms
- Current (I) = 0.06 A
- **Calculating Potential Difference:**
- Voltage drop across a section of wire (Vd) = IRd
- Voltage drop across 50 cm section = 0.06 A * 0.5 m * 100 ohms
- Voltage drop across 50 cm section = 3 V
- **Conclusion:**
- The potential difference between the two points on the wire, separated by a distance of 50 cm, will be 3 V.
- The correct answer is option 'C' (3 V).
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A 6 V battery is connected to the terminals of a 3 m long wire of uniform thickness and of resistance 100 Ω. The potential difference between two points on the wire, separated by a distance of 50 cm will bea)1.5 Vb)2 Vc)3 Vd)1 VCorrect answer is option 'D'. Can you explain this answer?
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