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The length of a line segment is of
10
units and the coordinates of one-end-point are
(2, -3) If the abscissa of the other end is
10, find the ordinate of the other end.?
Most Upvoted Answer
The length of a line segment is of 10 units and the coordinates of one...
Given Information:
- Length of line segment = 10 units
- Coordinates of one end-point = (2, -3)
- Abscissa of the other end = 10

Explanation:
To find the ordinate of the other end of the line segment, we first need to understand the concept of distance formula and coordinate geometry.

Distance Formula:
The distance between two points (x1, y1) and (x2, y2) in a coordinate plane is given by the formula:
\[ \sqrt{(x2 - x1)^2 + (y2 - y1)^2} \]

Calculations:
Given that the length of the line segment is 10 units, and the coordinates of one end-point are (2, -3). Let the coordinates of the other end-point be (10, y).
Using the distance formula:
\[ \sqrt{(10 - 2)^2 + (y - (-3))^2} = 10 \]
Solving this equation, we get:
\[ \sqrt{8^2 + (y + 3)^2} = 10 \]
\[ 8^2 + (y + 3)^2 = 100 \]
\[ 64 + y^2 + 6y + 9 = 100 \]
\[ y^2 + 6y - 27 = 0 \]
Now, solve this quadratic equation to find the value of y.
Hence, the ordinate of the other end of the line segment is the solution to the above quadratic equation.
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The length of a line segment is of 10 units and the coordinates of one-end-point are(2, -3) If the abscissa of the other end is 10, find the ordinate of the other end.?
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