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The length of a line segment is of
10
units and the coordinates of one-end-point are (2,-3). If the abscissa of the other end is
10, find the ordinate of the other end.?
Most Upvoted Answer
The length of a line segment is of 10 units and the coordinates of one...
Given information:
- Length of line segment = 10 units
- Coordinates of one end-point = (2, -3)
- Abscissa of the other end = 10

Finding the ordinate of the other end:
- Let the coordinates of the other end-point be (10, y).
- Using the distance formula, we can find the distance between the two points:
- Distance = √[(x2 - x1)^2 + (y2 - y1)^2]
- Given distance = 10 units
- Substitute the values of the given point (2, -3) and the other point (10, y) into the formula.
- 10 = √[(10 - 2)^2 + (y - (-3))^2]
- 10 = √[8^2 + (y + 3)^2]
- 100 = 64 + (y + 3)^2
- (y + 3)^2 = 36
- y + 3 = ±6
- y = -3 ± 6
- Two possible values of y are obtained from the above equation.
- y = -3 + 6 = 3 or y = -3 - 6 = -9
Therefore, the ordinate of the other end can be either 3 or -9.
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The length of a line segment is of 10 units and the coordinates of one-end-point are (2,-3). If the abscissa of the other end is 10, find the ordinate of the other end.?
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