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The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.?
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Problem:
The length of a line segment is 13 units and the coordinates of one endpoint are (-6, 7). If the ordinate of the other endpoint is -1, find the abscissa of the other endpoint.
Solution:
Let the coordinates of the other endpoint be (x, -1).
We know that the distance between two points (x1, y1) and (x2, y2) is given by the formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Using this formula, we can find the value of x:
13 = sqrt((x - (-6))^2 + (-1 - 7)^2)
169 = (x + 6)^2 + 64
105 = (x + 6)^2
x + 6 = ±sqrt(105)
x = -6 ± sqrt(105)
Therefore, the abscissa of the other endpoint is -6 + sqrt(105) or -6 - sqrt(105).
Explanation:
To solve this problem, we used the formula for the distance between two points to find the value of x. We first assumed that the coordinates of the other endpoint are (x, -1) and then substituted these values in the formula. We then simplified the equation and solved for x. Finally, we found that the abscissa of the other endpoint is -6 + sqrt(105) or -6 - sqrt(105).
The length of a line segment is 13 units and the coordinates of one endpoint are (-6, 7). If the ordinate of the other endpoint is -1, find the abscissa of the other endpoint.
Solution:
Let the coordinates of the other endpoint be (x, -1).
We know that the distance between two points (x1, y1) and (x2, y2) is given by the formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Using this formula, we can find the value of x:
13 = sqrt((x - (-6))^2 + (-1 - 7)^2)
169 = (x + 6)^2 + 64
105 = (x + 6)^2
x + 6 = ±sqrt(105)
x = -6 ± sqrt(105)
Therefore, the abscissa of the other endpoint is -6 + sqrt(105) or -6 - sqrt(105).
Explanation:
To solve this problem, we used the formula for the distance between two points to find the value of x. We first assumed that the coordinates of the other endpoint are (x, -1) and then substituted these values in the formula. We then simplified the equation and solved for x. Finally, we found that the abscissa of the other endpoint is -6 + sqrt(105) or -6 - sqrt(105).
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The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.?
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The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.?.
The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The length of a line segment is 13 units and the coordinates of one end point are ( -6 , 7). If the ordinate of the other end point is -1, find the abscissa of the other end point.?.
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