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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
 
  • a)
    39,30
  • b)
    41,32
  • c)

    42,33
  • d)

    43, 34
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Two students appeared at an examination. One of them secured 9 marks m...
Given Information:
- Let the marks obtained by the first student be x
- Marks obtained by the second student = x + 9
- According to the given condition, x + (x + 9) = 56% of the sum of their marks

Calculations:
- x + (x + 9) = 0.56(x + x + 9)
- 2x + 9 = 0.56(2x + 9)
- 2x + 9 = 1.12x + 5.04
- 9 - 5.04 = 1.12x - 2x
- 3.96 = 0.12x
- x = 33

Final Marks:
- Marks obtained by the first student = x = 33
- Marks obtained by the second student = x + 9 = 33 + 9 = 42
Therefore, the marks obtained by the students are 33 and 42, which corresponds to option 'D'.
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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:a)39,30b)41,32c)42,33d)43, 34Correct answer is option 'D'. Can you explain this answer?
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