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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO...
Identification of Organic Compound Using H NMR Spectrum
Given Data:
- Chemical formula: C3H7NO
- Signals in H NMR spectrum:
- 87.8 ppm (1H, singlet)
- 2.8 ppm (3H, singlet)
- 2.6 ppm (3H, singlet)
Analysis:
- The signal at 87.8 ppm indicates the presence of a hydrogen atom attached to a nitrogen atom, as the chemical shift for such a proton is typically in this range.
- The singlet nature of the peak suggests that this hydrogen is not split by any neighboring protons.
- The signals at 2.8 ppm and 2.6 ppm are likely methyl groups, each containing 3 hydrogen atoms, based on their integration values and chemical shifts.
Conclusion:
- Based on the H NMR spectrum data, the compound is likely to be Dimethylformamide (DMF), which has the chemical formula C3H7NO.
- In DMF, the signal at 87.8 ppm corresponds to the hydrogen attached to the nitrogen atom, while the signals at 2.8 ppm and 2.6 ppm correspond to the methyl groups.
- Therefore, the given H NMR spectrum is consistent with the structure of Dimethylformamide.
Given Data:
- Chemical formula: C3H7NO
- Signals in H NMR spectrum:
- 87.8 ppm (1H, singlet)
- 2.8 ppm (3H, singlet)
- 2.6 ppm (3H, singlet)
Analysis:
- The signal at 87.8 ppm indicates the presence of a hydrogen atom attached to a nitrogen atom, as the chemical shift for such a proton is typically in this range.
- The singlet nature of the peak suggests that this hydrogen is not split by any neighboring protons.
- The signals at 2.8 ppm and 2.6 ppm are likely methyl groups, each containing 3 hydrogen atoms, based on their integration values and chemical shifts.
Conclusion:
- Based on the H NMR spectrum data, the compound is likely to be Dimethylformamide (DMF), which has the chemical formula C3H7NO.
- In DMF, the signal at 87.8 ppm corresponds to the hydrogen attached to the nitrogen atom, while the signals at 2.8 ppm and 2.6 ppm correspond to the methyl groups.
- Therefore, the given H NMR spectrum is consistent with the structure of Dimethylformamide.
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?.
In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?.
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