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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7NO), exhibited signals at 7.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7NO)...



Identification of Organic Compound from H NMR Spectrum
Identifying an organic compound based on its H NMR spectrum involves analyzing the chemical shifts and integration values of the peaks. In this case, the compound has a molecular formula of C3H7NO and exhibits signals at 7.8 (1H, s), 2.8 (3H, s), and 2.6 (3H, s).

Chemical Shift Analysis
- The signal at 7.8 ppm corresponds to a singlet with 1H, which is typically indicative of an aromatic proton.
- The signals at 2.8 ppm and 2.6 ppm are also singlets, indicating the presence of methyl groups.

Interpretation
- The signal at 7.8 ppm suggests the presence of an aromatic proton, which narrows down the possibilities for the structure.
- The singlets at 2.8 ppm and 2.6 ppm indicate methyl groups, further aiding in the identification process.

Conclusion
Based on the H NMR spectrum provided, the compound is likely to be 3-methyl-2-nitrophenol (C3H7NO). The chemical shifts and integration values align with the expected signals for this compound, confirming its identity.
Overall, by carefully analyzing the H NMR spectrum and interpreting the chemical shifts and integration values, the organic compound can be successfully identified as 3-methyl-2-nitrophenol.
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C3H7NO), exhibited signals at 7.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?
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