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In a region of uniform electric field, as an electron travels from A to B, it slows from Ua= 6.1×10^6m/s to Ub=4.5×10^6m/s. What is its potential change ∆V = Vb - Va in volts?
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In a region of uniform electric field, as an electron travels from A t...
Understanding the Problem
In a uniform electric field, the potential difference (∆V) is related to the change in kinetic energy of a charged particle, such as an electron. When the electron moves from point A to point B, it experiences a change in speed, which indicates a change in kinetic energy and thus a change in electric potential energy.
Given Data
- Initial speed (Ua) = 6.1 × 10^6 m/s
- Final speed (Ub) = 4.5 × 10^6 m/s
- Mass of an electron (m) = 9.11 × 10^-31 kg
- Charge of an electron (q) = -1.6 × 10^-19 C
Change in Kinetic Energy
- The initial kinetic energy (KEa) at point A can be calculated using the formula:
KEa = (1/2) * m * Ua^2
- The final kinetic energy (KEb) at point B is:
KEb = (1/2) * m * Ub^2
- The change in kinetic energy (∆KE) is given by:
∆KE = KEb - KEa
Potential Change Calculation
- The work done on the electron by the electric field is equal to the change in kinetic energy:
W = ∆KE = q * ∆V
- Rearranging gives:
∆V = ∆KE / q
Conclusion
1. Calculate ∆KE using the speeds of the electron.
2. Use the charge of the electron to find the potential change (∆V).
3. The potential difference (Vb - Va) will be negative, indicating that the electron moves to a region of lower potential as it slows down.
This analysis helps understand how an electron's motion is influenced by electric fields and potential differences.
In a uniform electric field, the potential difference (∆V) is related to the change in kinetic energy of a charged particle, such as an electron. When the electron moves from point A to point B, it experiences a change in speed, which indicates a change in kinetic energy and thus a change in electric potential energy.
Given Data
- Initial speed (Ua) = 6.1 × 10^6 m/s
- Final speed (Ub) = 4.5 × 10^6 m/s
- Mass of an electron (m) = 9.11 × 10^-31 kg
- Charge of an electron (q) = -1.6 × 10^-19 C
Change in Kinetic Energy
- The initial kinetic energy (KEa) at point A can be calculated using the formula:
KEa = (1/2) * m * Ua^2
- The final kinetic energy (KEb) at point B is:
KEb = (1/2) * m * Ub^2
- The change in kinetic energy (∆KE) is given by:
∆KE = KEb - KEa
Potential Change Calculation
- The work done on the electron by the electric field is equal to the change in kinetic energy:
W = ∆KE = q * ∆V
- Rearranging gives:
∆V = ∆KE / q
Conclusion
1. Calculate ∆KE using the speeds of the electron.
2. Use the charge of the electron to find the potential change (∆V).
3. The potential difference (Vb - Va) will be negative, indicating that the electron moves to a region of lower potential as it slows down.
This analysis helps understand how an electron's motion is influenced by electric fields and potential differences.
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In a region of uniform electric field, as an electron travels from A to B, it slows from Ua= 6.1×10^6m/s to Ub=4.5×10^6m/s. What is its potential change ∆V = Vb - Va in volts?
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In a region of uniform electric field, as an electron travels from A to B, it slows from Ua= 6.1×10^6m/s to Ub=4.5×10^6m/s. What is its potential change ∆V = Vb - Va in volts? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a region of uniform electric field, as an electron travels from A to B, it slows from Ua= 6.1×10^6m/s to Ub=4.5×10^6m/s. What is its potential change ∆V = Vb - Va in volts? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a region of uniform electric field, as an electron travels from A to B, it slows from Ua= 6.1×10^6m/s to Ub=4.5×10^6m/s. What is its potential change ∆V = Vb - Va in volts?.
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