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0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is?
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0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete we...
Understanding the Reaction
When an acid reacts with a base like NaOH, it undergoes a neutralization reaction. In this case, we have 0.1 M NaOH reacting with a certain amount of acid.
Calculating Moles of NaOH
- Volume of NaOH = 20 ml = 0.020 L
- Molarity of NaOH = 0.1 M
- Moles of NaOH = Molarity × Volume = 0.1 × 0.020 = 0.002 moles
Stoichiometry of the Reaction
Assuming the reaction is a simple 1:1 reaction (common for monoprotic acids):
- Moles of acid = Moles of NaOH = 0.002 moles
Calculating the Molar Mass of the Acid
Now we need to find the mass of acid that corresponds to 0.002 moles:
- Given weight of acid = 0.126 grams
- Molar mass = Mass / Moles
- Molar mass = 0.126 grams / 0.002 moles = 63 grams/mole
Conclusion
The complete weight of the acid used in this neutralization reaction is calculated to be:
- 0.126 grams of the acid corresponds to 0.002 moles, with a molar mass of 63 grams/mole.
This information is crucial for understanding the acid-base reaction and determining the properties of the acid involved in the neutralization process.
When an acid reacts with a base like NaOH, it undergoes a neutralization reaction. In this case, we have 0.1 M NaOH reacting with a certain amount of acid.
Calculating Moles of NaOH
- Volume of NaOH = 20 ml = 0.020 L
- Molarity of NaOH = 0.1 M
- Moles of NaOH = Molarity × Volume = 0.1 × 0.020 = 0.002 moles
Stoichiometry of the Reaction
Assuming the reaction is a simple 1:1 reaction (common for monoprotic acids):
- Moles of acid = Moles of NaOH = 0.002 moles
Calculating the Molar Mass of the Acid
Now we need to find the mass of acid that corresponds to 0.002 moles:
- Given weight of acid = 0.126 grams
- Molar mass = Mass / Moles
- Molar mass = 0.126 grams / 0.002 moles = 63 grams/mole
Conclusion
The complete weight of the acid used in this neutralization reaction is calculated to be:
- 0.126 grams of the acid corresponds to 0.002 moles, with a molar mass of 63 grams/mole.
This information is crucial for understanding the acid-base reaction and determining the properties of the acid involved in the neutralization process.
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0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is?
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0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is?.
0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.126 gram of an acid is required to 20 ml of 0.1 NaOH for complete weight of acid is?.
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