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Practice Quiz or MCQ (Multiple Choice Questions) with solutions are available for Practice, which would help you prepare for "Quadratic Equations" under Quantitative Aptitude. You can practice these practice quizzes as per your speed and improvise the topic. The same topic is covered under various competitive examinations like - CAT, GMAT, Bank PO, SSC and other competitive examinations.
Q. Find the roots of the quadratic equation: x2 + 2x - 15 = 0?
- a)-5, 3
- b)3, 5
- c)-3, 5
- d)-3, -5
- e)5, 2
Correct answer is option 'A'. Can you explain this answer?
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Practice Quiz or MCQ (Multiple Choice Questions) with solutions are av...
Rules for factorising:
ax^2 + bx + c = 0
m x n = c
m + n = b
∴(x+m)(x+n)=0
In this case: 5 x −3 = −15 = c
5 + −3 = 2 = b
∴ x^2 + 2x −15 = 0 → (x+5)(x−3) = 0
Either of the brackets must be equal to 0.
Assuming (x+5) = 0:
x = −5
Assuming (x-3) = 0:
x= 3
Most Upvoted Answer
Practice Quiz or MCQ (Multiple Choice Questions) with solutions are av...
1.multiply 1st term and last term of the eqn: 1*15 =15
2.now, find factors of 15 that sum of those two factors is the middle term of the eqn.
5 and -3 : when multiplied ans is: -15
and when added ans is: +2
3.change the sign of the factors i.e now factors are -5 and 3
therefore ans is: -5 , 3 (option A)
2.now, find factors of 15 that sum of those two factors is the middle term of the eqn.
5 and -3 : when multiplied ans is: -15
and when added ans is: +2
3.change the sign of the factors i.e now factors are -5 and 3
therefore ans is: -5 , 3 (option A)
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Practice Quiz or MCQ (Multiple Choice Questions) with solutions are av...
Finding the Roots of a Quadratic Equation
To find the roots of a quadratic equation, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / 2a
Where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
Solving the Equation
Given the quadratic equation x² + 2x - 15 = 0, we can identify the coefficients:
a = 1
b = 2
c = -15
Substituting these values into the quadratic formula, we get:
x = (-2 ± √(2² - 4(1)(-15))) / 2(1)
x = (-2 ± √(4 + 60)) / 2
x = (-2 ± √64) / 2
Simplifying, we get:
x = (-2 + 8) / 2 or x = (-2 - 8) / 2
x = 6 / 2 or x = -10 / 2
x = 3 or x = -5
Therefore, the roots of the quadratic equation x² + 2x - 15 = 0 are x = 3 and x = -5.
Answer
The correct answer is option A, which lists the roots as -5 and 3.
To find the roots of a quadratic equation, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / 2a
Where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
Solving the Equation
Given the quadratic equation x² + 2x - 15 = 0, we can identify the coefficients:
a = 1
b = 2
c = -15
Substituting these values into the quadratic formula, we get:
x = (-2 ± √(2² - 4(1)(-15))) / 2(1)
x = (-2 ± √(4 + 60)) / 2
x = (-2 ± √64) / 2
Simplifying, we get:
x = (-2 + 8) / 2 or x = (-2 - 8) / 2
x = 6 / 2 or x = -10 / 2
x = 3 or x = -5
Therefore, the roots of the quadratic equation x² + 2x - 15 = 0 are x = 3 and x = -5.
Answer
The correct answer is option A, which lists the roots as -5 and 3.
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Practice Quiz or MCQ (Multiple Choice Questions) with solutions are available for Practice, which would help you prepare for"Quadratic Equations"under Quantitative Aptitude. You can practice these practice quizzes as per your speed and improvise the topic. The same topic is covered under various competitive examinations like - CAT, GMAT, Bank PO, SSC and other competitive examinations.Q.Find the roots of the quadratic equation: x2+ 2x - 15 = 0?a)-5, 3b)3, 5c)-3, 5d)-3, -5e)5, 2Correct answer is option 'A'. Can you explain this answer?
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