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A can do a piece of work in 20 days. He works at it for 5 days and then B finishes it in 10 moredays. In how many days will A and B together finish the work?
- a)8 days
- b)10 days
- c)12 days
- d)6 days
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A can do a piece of work in 20 days. He works at it for 5 days and the...
Work done by A in 5 days = 1/20*5
=1/4
remaining work=(1-1/4)
=3/4
now,3/4 work is done by B in 10 days
whole work will be done by B in 10*4/3= 40/3 days
as 1 day's work of A = 1/20
1 day's work of B =3/40
(A+B)'s 1 day's work= 1/20+3/40
= 1/8
so,both finished the work in 8 day's.
Most Upvoted Answer
A can do a piece of work in 20 days. He works at it for 5 days and the...
Given:
A can do a piece of work in 20 days.
A works for 5 days
B finishes it in 10 more days.
To find:
In how many days will A and B together finish the work?
Solution:
Let's assume the total work is 20 units (LCM of 20 and 10).
Work done by A in 5 days = (5/20) * 20 = 5 units
Remaining work = 20 - 5 = 15 units
B completes the remaining work in 10 days, so B's one day work = (15/10) = 1.5 units
Now, let's assume A's one day work = x units.
So, A can complete the total work in 20 days, hence A's one day work = (20/20) = 1 unit/day
Total work done by A and B in one day = A's one day work + B's one day work
x + 1.5 = (20/20) = 1
x = 1 - 1.5 = -0.5 (This is not possible as work done can't be negative)
So, A and B working together cannot complete the work in less than 10 days.
Now, let's assume A and B together complete the work in 'n' days.
Work done by A in 'n' days = (n/20) * 20 = n units
Work done by B in 'n' days = (n/10) * 1.5 = 1.5n units
Total work done by A and B in 'n' days = n + 1.5n = 2.5n units
As per the given condition, the total work done by A and B together = 20 units
So, 2.5n = 20
n = 8
Therefore, A and B together will finish the work in 8 days. Hence, option A is the correct answer.
A can do a piece of work in 20 days.
A works for 5 days
B finishes it in 10 more days.
To find:
In how many days will A and B together finish the work?
Solution:
Let's assume the total work is 20 units (LCM of 20 and 10).
Work done by A in 5 days = (5/20) * 20 = 5 units
Remaining work = 20 - 5 = 15 units
B completes the remaining work in 10 days, so B's one day work = (15/10) = 1.5 units
Now, let's assume A's one day work = x units.
So, A can complete the total work in 20 days, hence A's one day work = (20/20) = 1 unit/day
Total work done by A and B in one day = A's one day work + B's one day work
x + 1.5 = (20/20) = 1
x = 1 - 1.5 = -0.5 (This is not possible as work done can't be negative)
So, A and B working together cannot complete the work in less than 10 days.
Now, let's assume A and B together complete the work in 'n' days.
Work done by A in 'n' days = (n/20) * 20 = n units
Work done by B in 'n' days = (n/10) * 1.5 = 1.5n units
Total work done by A and B in 'n' days = n + 1.5n = 2.5n units
As per the given condition, the total work done by A and B together = 20 units
So, 2.5n = 20
n = 8
Therefore, A and B together will finish the work in 8 days. Hence, option A is the correct answer.
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Community Answer
A can do a piece of work in 20 days. He works at it for 5 days and the...
A=20day
A do work for 5 day and remaining work is 15 and B finish this remaining work in 10 days their efficiency is
A*15=B*10
A/B=2/3
total work= efficiency*time from A
total work=2*20=40
both complete in 40/(2+3)
8 days
A do work for 5 day and remaining work is 15 and B finish this remaining work in 10 days their efficiency is
A*15=B*10
A/B=2/3
total work= efficiency*time from A
total work=2*20=40
both complete in 40/(2+3)
8 days
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A can do a piece of work in 20 days. He works at it for 5 days and then B finishes it in 10 moredays. In how many days will A and B together finish the work?a)8 daysb)10 daysc)12 daysd)6 daysCorrect answer is option 'A'. Can you explain this answer?
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