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It takes 10 s and 15 s, respectively, for two trains travelling at different constant speeds to
completely pass a telegraph post. The length of the first train is 120 m and that of the second train is
150 m. The magnitude of the difference in the speeds of the two trains (in m/s) is ____________.
completely pass a telegraph post. The length of the first train is 120 m and that of the second train is
150 m. The magnitude of the difference in the speeds of the two trains (in m/s) is ____________.
- a)2.0
- b)10.0
- c)12.0
- d)22.0
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
It takes 10 s and 15 s, respectively, for two trains travelling at dif...
Given:
- Length of the first train = 120 m
- Length of the second train = 150 m
- Time taken by the first train to pass a telegraph post = 10 s
- Time taken by the second train to pass a telegraph post = 15 s
To find:
The magnitude of the difference in the speeds of the two trains.
Formula:
Speed = Distance/Time
Calculation:
Let the speed of the first train be v1 m/s and the speed of the second train be v2 m/s.
Distance covered by the first train in 10 seconds = 120 m
Distance covered by the second train in 15 seconds = 150 m
Therefore, we have the following equations:
v1 * 10 = 120 ...(1)
v2 * 15 = 150 ...(2)
Simplifying equation (1), we get:
v1 = 120/10 = 12 m/s
Simplifying equation (2), we get:
v2 = 150/15 = 10 m/s
The magnitude of the difference in the speeds of the two trains is given by |v1 - v2|.
Therefore, the magnitude of the difference in the speeds of the two trains = |12 - 10| = 2 m/s.
Hence, the correct answer is option A) 2.0.
- Length of the first train = 120 m
- Length of the second train = 150 m
- Time taken by the first train to pass a telegraph post = 10 s
- Time taken by the second train to pass a telegraph post = 15 s
To find:
The magnitude of the difference in the speeds of the two trains.
Formula:
Speed = Distance/Time
Calculation:
Let the speed of the first train be v1 m/s and the speed of the second train be v2 m/s.
Distance covered by the first train in 10 seconds = 120 m
Distance covered by the second train in 15 seconds = 150 m
Therefore, we have the following equations:
v1 * 10 = 120 ...(1)
v2 * 15 = 150 ...(2)
Simplifying equation (1), we get:
v1 = 120/10 = 12 m/s
Simplifying equation (2), we get:
v2 = 150/15 = 10 m/s
The magnitude of the difference in the speeds of the two trains is given by |v1 - v2|.
Therefore, the magnitude of the difference in the speeds of the two trains = |12 - 10| = 2 m/s.
Hence, the correct answer is option A) 2.0.
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Community Answer
It takes 10 s and 15 s, respectively, for two trains travelling at dif...
Speed=distance/time
=(length of train + length of post)/time
length of post=negligible
speed of train 1 = 120/10=12m/s
speed of train 2 = 150/15=10m/s
difference in speed = 12-10=2m/s
=(length of train + length of post)/time
length of post=negligible
speed of train 1 = 120/10=12m/s
speed of train 2 = 150/15=10m/s
difference in speed = 12-10=2m/s
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It takes 10 s and 15 s, respectively, for two trains travelling at different constant speeds tocompletely pass a telegraph post. The length of the first train is 120 m and that of the second train is150 m. The magnitude of the difference in the speeds of the two trains (in m/s) is ____________.a)2.0b)10.0c)12.0d)22.0Correct answer is option 'A'. Can you explain this answer?
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