In an exam of two papers maths and chemistry, 60% of the students pass...
Since, we have to find the minimum percentage, it can be possible that no one has failed in both the subjects.
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In an exam of two papers maths and chemistry, 60% of the students pass...
I had a problem with this one but I finally understood it . here it goes ...so the fail percentage is 30 in chemistry and 40 in mathematics so that means out of 10 students assumimg named 1-10 the first three failed in chemistry (i.e 1,2,3) and the students from (4,5,6,7) failed in mathematics thus none of them failed in both
In an exam of two papers maths and chemistry, 60% of the students pass...
Given:
- Percentage of students passing in maths = 60%
- Percentage of students passing in chemistry = 70%
To find:
- Minimum percentage of students who could have failed in both the subjects
Approach:
- We know that the total percentage of students who passed in at least one subject cannot be greater than 100%.
- Using this fact, we can find the minimum percentage of students who could have failed in both subjects.
Calculation:
- Let's assume that all the students who passed in maths also passed in chemistry. Then, the total percentage of students who passed in at least one subject = 60%.
- Similarly, let's assume that all the students who passed in chemistry also passed in maths. Then, the total percentage of students who passed in at least one subject = 70%.
- Since both these assumptions cannot be true at the same time, the actual percentage of students who passed in at least one subject lies between 60% and 70%.
- Therefore, the minimum percentage of students who could have failed in both subjects = 100% - (percentage of students who passed in at least one subject)
- = 100% - (between 60% and 70%)
- = 0% to 40%
- Since we need to find the minimum percentage, the answer is 0%.
Therefore, option (A) is the correct answer.