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A human male produces sperms with the genotypes AB, Ab, aB, ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?
- a)AABB
- b)AaBb
- c)AABb
- d)AaBB
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A human male produces sperms with the genotypes AB, Ab, aB, ab pertain...
If the genotype is AaBb the alleles that will be produced will be AB, Ab, aB, ab, since there are two diallelic characters in the genotypes the person must be heterozygous for both genes. AABB is homozygous. So, the correct answer is "AaBb".
Most Upvoted Answer
A human male produces sperms with the genotypes AB, Ab, aB, ab pertain...
Genotype of a human male producing sperms with the genotypes AB, Ab, aB, ab pertaining to two diallelic characters in equal proportions can be found by performing a dihybrid cross.
Dihybrid cross involves the inheritance of two different traits. In this case, the two traits are represented by two different genes. Let's assume the two genes are A and B, and they are present on different chromosomes. Each gene has two alleles, A and a, and B and b, respectively.
Possible genotypes of the gametes that can be produced by the human male are:
- AB
- Ab
- aB
- ab
To determine the genotype of the person, we need to perform a Punnett square. Let's assume that the person is heterozygous for both genes (AaBb).
Possible gametes produced by the person are:
- AB (produced by A_B_)
- Ab (produced by A_bb)
- aB (produced by aaB_)
- ab (produced by aabb)
The Punnett square for the dihybrid cross between AaBb x AaBb would look like this:
| | A | a |
|---|---|---|
| B | AB | aB |
| b | Ab | ab |
The genotypes of the offspring are:
- 1/4 AABB (produced by AA_BB)
- 1/4 AaBB (produced by AaB_)
- 1/4 AABb (produced by A_Bb)
- 1/4 AaBb (produced by A_bb or aaB_)
Since the gametes produced by the person are AB, Ab, aB, and ab in equal proportions, we can assume that the probability of each gamete being produced is 1/4. Therefore, the probability of the person being AaBb is also 1/4.
Hence, the corresponding genotype of this person is AaBb.
Dihybrid cross involves the inheritance of two different traits. In this case, the two traits are represented by two different genes. Let's assume the two genes are A and B, and they are present on different chromosomes. Each gene has two alleles, A and a, and B and b, respectively.
Possible genotypes of the gametes that can be produced by the human male are:
- AB
- Ab
- aB
- ab
To determine the genotype of the person, we need to perform a Punnett square. Let's assume that the person is heterozygous for both genes (AaBb).
Possible gametes produced by the person are:
- AB (produced by A_B_)
- Ab (produced by A_bb)
- aB (produced by aaB_)
- ab (produced by aabb)
The Punnett square for the dihybrid cross between AaBb x AaBb would look like this:
| | A | a |
|---|---|---|
| B | AB | aB |
| b | Ab | ab |
The genotypes of the offspring are:
- 1/4 AABB (produced by AA_BB)
- 1/4 AaBB (produced by AaB_)
- 1/4 AABb (produced by A_Bb)
- 1/4 AaBb (produced by A_bb or aaB_)
Since the gametes produced by the person are AB, Ab, aB, and ab in equal proportions, we can assume that the probability of each gamete being produced is 1/4. Therefore, the probability of the person being AaBb is also 1/4.
Hence, the corresponding genotype of this person is AaBb.
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A human male produces sperms with the genotypes AB, Ab, aB, ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?a)AABBb)AaBbc)AABbd)AaBBCorrect answer is option 'B'. Can you explain this answer?
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