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S nth = distance travelled in nth second , Snth = u+( n-1/2)a , a=acc then 1.only numerically correct 2.only dimensionally correct 3.both 1 &2 4.non of these?
Most Upvoted Answer
S nth = distance travelled in nth second , Snth = u+( n-1/2)a , a=acc...
I think it's only numerically correct as L= LT-1 +LT-2 is not dimensionally correct
Community Answer
S nth = distance travelled in nth second , Snth = u+( n-1/2)a , a=acc...
It is dimensionally correct here s is the distance travelled in nth second means speed, u also has same dimension, and acceleration multiplied by nth second gives the dimension of velocity.
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S nth = distance travelled in nth second , Snth = u+( n-1/2)a , a=acc then 1.only numerically correct 2.only dimensionally correct 3.both 1 &2 4.non of these?
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