In an examination 80% of students passed in Mathematics and 75% of stu...
Pass maths = 80% fail maths = 20%
Pass eng = 75% fail eng = 25%
Fail in both = 15%
Total fail [n(A union B)] = 20+25-15=30%
Hence, total pass = 100-30 = 70%
490= 70% of x
= 70x/100
=700
In an examination 80% of students passed in Mathematics and 75% of stu...
Given information:
- 80% of students passed in Mathematics
- 75% of students passed in English
- 15% of students failed in both subjects
- 490 students passed in both subjects
To find:
- Total number of students who took the examination
Approach:
Let's assume the total number of students who took the examination as 'x'.
Then,
- Number of students who passed in Mathematics = 80% of x
- Number of students who passed in English = 75% of x
- Number of students who failed in both subjects = 15% of x
- Number of students who passed in at least one subject = Total number of students - Number of students who failed in both subjects
Using the above information, we can form the following equation:
80% of x + 75% of x - 15% of x = Total number of students - 15% of x
Simplifying the above equation, we get:
140% of x = Total number of students - 15% of x + 490
155% of x = Total number of students + 490
x = (Total number of students + 490) / 1.55
Now, we need to find the value of 'x' to get the total number of students who took the examination.
Calculation:
Substituting the options in the above equation, we get:
Option A: (800 + 490) / 1.55 = 935.48
Option B: (700 + 490) / 1.55 = 806.45
Option C: (900 + 490) / 1.55 = 1045.16
Option D: (750 + 490) / 1.55 = 903.23
Out of the given options, option B gives us the closest value to 'x'.
Therefore, the total number of students who took the examination is 700.
Final Answer:
The correct option is B) 700.