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A body of mass 3 kg is moving along a straight line with a velocity of 24 m/s . when it is at a point 'p' a force of 9N acts on the body in direction opposite to it's motion. The time after which it will be at 'p' again a.8s b.16s c.12s d.24s?
Most Upvoted Answer
A body of mass 3 kg is moving along a straight line with a velocity of...
Given:
- Mass of the body, m = 3 kg
- Velocity of the body, v = 24 m/s
- Force acting on the body, F = 9 N (opposite to the direction of motion)

Required:
To find the time after which the body will be at point 'P' again.

Explanation:
To solve this problem, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

Step 1: Finding the acceleration:
We can use the formula:
F = ma
where F is the force acting on the body and a is the acceleration produced.
Rearranging the formula, we get:
a = F/m

Given, F = 9 N and m = 3 kg
Substituting the values, we get:
a = 9/3 = 3 m/s²

Step 2: Finding the time:
We can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

Given, u = 24 m/s, a = -3 m/s² (negative because the force is opposite to the direction of motion)
Substituting the values, we get:
0 = 24 + (-3)t
-24 = -3t
Dividing both sides by -3, we get:
t = 8 s

Therefore, the time after which the body will be at point 'P' again is 8 seconds.

Answer:
The correct option is a. 8s.
Community Answer
A body of mass 3 kg is moving along a straight line with a velocity of...
B is correct option
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A body of mass 3 kg is moving along a straight line with a velocity of 24 m/s . when it is at a point 'p' a force of 9N acts on the body in direction opposite to it's motion. The time after which it will be at 'p' again a.8s b.16s c.12s d.24s?
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