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A parallel plate capacitor has rectangular plates 400cm2 area and are separated by a distance of 2mm with air as the medium. What charge will appear on the plates if a 200 volt potential difference is applied across the capacitor?
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A parallel plate capacitor has rectangular plates 400cm2 area and are ...
Calculation of Charge on a Parallel Plate Capacitor


Given Data:


  • Area of rectangular plates = 400 cm2

  • Distance between the plates = 2 mm

  • Potential difference applied = 200 V



Formula:

The capacitance of a parallel plate capacitor is given by:

C = ε0A/d

Where,


  • C = Capacitance

  • ε0 = Permittivity of free space = 8.85 x 10-12 F/m

  • A = Area of the plates

  • d = Distance between the plates



The charge on the capacitor is given by:

Q = CV

Where,


  • Q = Charge on the capacitor

  • C = Capacitance

  • V = Potential difference applied



Solution:

Converting the area of the plates to m2:

Area of the plates = 400 cm2 = 0.04 m2


Converting the distance between the plates to m:

Distance between the plates = 2 mm = 0.002 m


Calculating the capacitance of the capacitor:

C = ε0A/d = 8.85 x 10-12 x 0.04/0.002 = 1.77 x 10-10 F


Calculating the charge on the capacitor:

Q = CV = 1.77 x 10-10 x 200 = 3.54 x 10-8 C


Conclusion:

The charge on the parallel plate capacitor is 3.54 x 10-8 C.
Community Answer
A parallel plate capacitor has rectangular plates 400cm2 area and are ...
4000C. right?
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A parallel plate capacitor has rectangular plates 400cm2 area and are separated by a distance of 2mm with air as the medium. What charge will appear on the plates if a 200 volt potential difference is applied across the capacitor?
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