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A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.?
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A body of mass 2kg is displaced by 5m by applying a force of 10N in di...
Frictional force is the force that opposes the motion of an object when it is in contact with a surface. It is dependent on the coefficient of friction and the normal force.
Given:
Mass of the body (m) = 2 kg
Displacement (d) = 5 m
Applied force (F) = 10 N
Coefficient of friction (μ) = 0.4
To find: Frictional force (Ff)
1. Calculating the Normal Force:
The normal force (Fn) is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface.
The normal force can be calculated using the formula:
Fn = m * g
where m is the mass of the body and g is the acceleration due to gravity (approximately 9.8 m/s²).
Given: m = 2 kg
Using the formula, Fn = 2 kg * 9.8 m/s²
Fn = 19.6 N
2. Calculating the Applied Force in the Direction of Motion:
Since the applied force is in the direction of displacement, the work done can be calculated using the formula:
Work (W) = F * d
where F is the applied force and d is the displacement.
Given: F = 10 N, d = 5 m
Using the formula, W = 10 N * 5 m
W = 50 J (Joules)
3. Calculating the Work Done Against Friction:
The work done against friction is equal to the product of the frictional force and the displacement. It can be calculated using the formula:
Work (W) = Ff * d
where Ff is the frictional force and d is the displacement.
Given: d = 5 m
Using the formula, 50 J = Ff * 5 m
Ff = 50 J / 5 m
Ff = 10 N
Therefore, the frictional force acting on the body is 10N.
Given:
Mass of the body (m) = 2 kg
Displacement (d) = 5 m
Applied force (F) = 10 N
Coefficient of friction (μ) = 0.4
To find: Frictional force (Ff)
1. Calculating the Normal Force:
The normal force (Fn) is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface.
The normal force can be calculated using the formula:
Fn = m * g
where m is the mass of the body and g is the acceleration due to gravity (approximately 9.8 m/s²).
Given: m = 2 kg
Using the formula, Fn = 2 kg * 9.8 m/s²
Fn = 19.6 N
2. Calculating the Applied Force in the Direction of Motion:
Since the applied force is in the direction of displacement, the work done can be calculated using the formula:
Work (W) = F * d
where F is the applied force and d is the displacement.
Given: F = 10 N, d = 5 m
Using the formula, W = 10 N * 5 m
W = 50 J (Joules)
3. Calculating the Work Done Against Friction:
The work done against friction is equal to the product of the frictional force and the displacement. It can be calculated using the formula:
Work (W) = Ff * d
where Ff is the frictional force and d is the displacement.
Given: d = 5 m
Using the formula, 50 J = Ff * 5 m
Ff = 50 J / 5 m
Ff = 10 N
Therefore, the frictional force acting on the body is 10N.
Community Answer
A body of mass 2kg is displaced by 5m by applying a force of 10N in di...
8N
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A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.?
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A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.?.
A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2kg is displaced by 5m by applying a force of 10N in direction of displacement. For surface co efficient of friction is 0.4 ,find frictional force? A.2N B.4N C.8N D.10N Please give explanation.?.
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