A man in a lift carrying a bag of 5 kg in lift moves downwards with g/2 acceleration. Find tension in the handle of the bag.



To solve this problem, we need to use Newton's second law of motion which states that the force acting on an object is equal to the product of its mass and acceleration.



Given values in the problem are:

- Mass of the bag = 5 kg
- Acceleration of the lift = g/2 (moving downwards)
- We need to find the tension in the handle of the bag.



In this problem, we have two forces acting on the bag:

- The weight of the bag (mg) acting downwards
- The tension in the handle of the bag (T) acting upwards

Therefore, the free-body diagram of the bag is as follows:

```
T
|
|
|
mg
```



The net force acting on the bag is given by:

```
Net force = T - mg
```

According to Newton's second law of motion, this net force is equal to the product of the mass of the bag and its acceleration:

```
T - mg = ma
```

Substituting the given values, we get:

```
T - 5g/2 = 5(g/2)
T - 5g/2 = 5g/2
T = 10g/2
T = 5g
```

Therefore, the tension in the handle of the bag is 5g.



The gravitational acceleration (g) is 9.8 m/s^2. Therefore, the tension in the handle of the bag is:

```
T = 5g
T = 5 x 9.8
T = 49 N
```

Therefore, the tension in the handle of the bag is 49 N.

Tension = m× (g - g/2 ) = (mg)/2 = (5× 9.8)÷2 =24.5 N