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At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by?
Most Upvoted Answer
At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without c...
Explanation:
To determine the decrease in the partial pressure of O2 when it is removed from the container, we need to consider the initial and final conditions of the system.
Initial conditions:
- 1 mole of He
- 2 moles of Ne
- 3 moles of N2
- Total pressure remains constant at STP
Step 1: Calculate the initial total pressure:
At STP, the total pressure is 1 atm.
Step 2: Calculate the initial partial pressures of each gas:
Using the ideal gas law (PV = nRT), we can calculate the initial partial pressures of He, Ne, and N2.
- For He:
PV = nRT
P(He) = (1 mol)(0.0821 L.atm/mol.K)(273 K) / (V)
P(He) = (0.0821)(273) / (V)
- For Ne:
PV = nRT
P(Ne) = (2 mol)(0.0821 L.atm/mol.K)(273 K) / (V)
P(Ne) = (0.0821)(273)(2) / (V)
- For N2:
PV = nRT
P(N2) = (3 mol)(0.0821 L.atm/mol.K)(273 K) / (V)
P(N2) = (0.0821)(273)(3) / (V)
Step 3: Calculate the partial pressure of O2:
Since O2 is not initially present in the container, its partial pressure is zero.
Step 4: Remove 2 moles of O2:
When 2 moles of O2 are removed from the container, the total number of moles decreases by 2.
Step 5: Recalculate the total pressure:
The total pressure remains constant at STP, so it remains 1 atm.
Step 6: Calculate the new partial pressure of O2:
Since 2 moles of O2 are removed, the partial pressure of O2 will be zero.
Step 7: Calculate the decrease in the partial pressure of O2:
The decrease in the partial pressure of O2 is the difference between the initial and final values.
Decrease in the partial pressure of O2 = 0 - 0 = 0 atm
Conclusion:
When 2 moles of O2 are removed from the container, the partial pressure of O2 decreases by 0 atm.
To determine the decrease in the partial pressure of O2 when it is removed from the container, we need to consider the initial and final conditions of the system.
Initial conditions:
- 1 mole of He
- 2 moles of Ne
- 3 moles of N2
- Total pressure remains constant at STP
Step 1: Calculate the initial total pressure:
At STP, the total pressure is 1 atm.
Step 2: Calculate the initial partial pressures of each gas:
Using the ideal gas law (PV = nRT), we can calculate the initial partial pressures of He, Ne, and N2.
- For He:
PV = nRT
P(He) = (1 mol)(0.0821 L.atm/mol.K)(273 K) / (V)
P(He) = (0.0821)(273) / (V)
- For Ne:
PV = nRT
P(Ne) = (2 mol)(0.0821 L.atm/mol.K)(273 K) / (V)
P(Ne) = (0.0821)(273)(2) / (V)
- For N2:
PV = nRT
P(N2) = (3 mol)(0.0821 L.atm/mol.K)(273 K) / (V)
P(N2) = (0.0821)(273)(3) / (V)
Step 3: Calculate the partial pressure of O2:
Since O2 is not initially present in the container, its partial pressure is zero.
Step 4: Remove 2 moles of O2:
When 2 moles of O2 are removed from the container, the total number of moles decreases by 2.
Step 5: Recalculate the total pressure:
The total pressure remains constant at STP, so it remains 1 atm.
Step 6: Calculate the new partial pressure of O2:
Since 2 moles of O2 are removed, the partial pressure of O2 will be zero.
Step 7: Calculate the decrease in the partial pressure of O2:
The decrease in the partial pressure of O2 is the difference between the initial and final values.
Decrease in the partial pressure of O2 = 0 - 0 = 0 atm
Conclusion:
When 2 moles of O2 are removed from the container, the partial pressure of O2 decreases by 0 atm.
Community Answer
At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without c...
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At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by?
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At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by?.
At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At STP, a container has 1 mole of He , 2 mole Ne , 3 mole N2 without changing total pressure if 2 mole of O2 is removed the partial of O2 will be decreased by?.
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