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If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details?
Most Upvoted Answer
If the weight of metal chloride is x gram containing y gram of metal,t...
Weight of metal = y g
Weight of chlorine = (x-y)
(x-y) g of chlorine = (x-y) / 35.5 moles
Chloride means the Cl has taken 2 electrons, hence a total of ((x-y)/17.75) moles
So, Equivalent weight of metal will comes out to be = y / ((x-y)/17.75)
Weight of chlorine = (x-y)
(x-y) g of chlorine = (x-y) / 35.5 moles
Chloride means the Cl has taken 2 electrons, hence a total of ((x-y)/17.75) moles
So, Equivalent weight of metal will comes out to be = y / ((x-y)/17.75)
Community Answer
If the weight of metal chloride is x gram containing y gram of metal,t...
Calculation of Equivalent Weight of Metal in Metal Chloride
Introduction:
The equivalent weight of a substance is the amount of substance that can combine or replace 1 mole of hydrogen (or any other chemical species) in a chemical reaction. Metal chloride is a type of compound in which a metal atom is combined with a chlorine atom. In this article, we will calculate the equivalent weight of the metal in metal chloride given the weight of metal chloride and the weight of metal.
Calculation Method:
To calculate the equivalent weight of metal in metal chloride, we need to use the following formula:
Equivalent weight of metal = (Weight of metal chloride / Weight of metal) x Atomic weight of chlorine
Where,
Weight of metal chloride = x gram
Weight of metal = y gram
Atomic weight of chlorine = 35.5 g/mol
Now, let's substitute the values in the above formula and simplify it.
1. E = (x / y) x 35.5
This formula assumes that the metal chloride is a binary compound and contains only one atom of metal and one atom of chlorine. However, most metal chlorides are not binary compounds and have a different number of atoms of chlorine and metal. Therefore, this formula is not correct.
2. E = 8(y - x) / x
This formula assumes that the metal in metal chloride has a valency of 2. Therefore, the formula uses the factor of 8 to calculate the equivalent weight of the metal. However, this assumption may not be correct for all metal chlorides. Therefore, this formula is also not correct.
3. E = y x 35.5 / (x - y)
This formula assumes that the metal in metal chloride has a valency of 1. Therefore, the formula uses the atomic weight of chlorine to calculate the equivalent weight of the metal. However, this formula does not take into account the number of atoms of metal and chlorine in the metal chloride. Therefore, this formula is also not correct.
4. E = 8(x - y) / y
This formula assumes that the metal in metal chloride has a valency of 2. Therefore, the formula uses the factor of 8 to calculate the equivalent weight of the metal. However, this formula takes into account the number of atoms of metal and chlorine in the metal chloride. Therefore, this formula is correct for metal chlorides with a valency of 2.
Conclusion:
The correct formula for calculating the equivalent weight of metal in metal chloride depends on the valency of the metal in the compound. For metal chlorides with a valency of 2, the formula E = 8(x - y) / y is correct. However, for metal chlorides with a valency of 1, the formula for calculating the equivalent weight of the metal is more complex and depends on the specific metal and its valency.
Introduction:
The equivalent weight of a substance is the amount of substance that can combine or replace 1 mole of hydrogen (or any other chemical species) in a chemical reaction. Metal chloride is a type of compound in which a metal atom is combined with a chlorine atom. In this article, we will calculate the equivalent weight of the metal in metal chloride given the weight of metal chloride and the weight of metal.
Calculation Method:
To calculate the equivalent weight of metal in metal chloride, we need to use the following formula:
Equivalent weight of metal = (Weight of metal chloride / Weight of metal) x Atomic weight of chlorine
Where,
Weight of metal chloride = x gram
Weight of metal = y gram
Atomic weight of chlorine = 35.5 g/mol
Now, let's substitute the values in the above formula and simplify it.
1. E = (x / y) x 35.5
This formula assumes that the metal chloride is a binary compound and contains only one atom of metal and one atom of chlorine. However, most metal chlorides are not binary compounds and have a different number of atoms of chlorine and metal. Therefore, this formula is not correct.
2. E = 8(y - x) / x
This formula assumes that the metal in metal chloride has a valency of 2. Therefore, the formula uses the factor of 8 to calculate the equivalent weight of the metal. However, this assumption may not be correct for all metal chlorides. Therefore, this formula is also not correct.
3. E = y x 35.5 / (x - y)
This formula assumes that the metal in metal chloride has a valency of 1. Therefore, the formula uses the atomic weight of chlorine to calculate the equivalent weight of the metal. However, this formula does not take into account the number of atoms of metal and chlorine in the metal chloride. Therefore, this formula is also not correct.
4. E = 8(x - y) / y
This formula assumes that the metal in metal chloride has a valency of 2. Therefore, the formula uses the factor of 8 to calculate the equivalent weight of the metal. However, this formula takes into account the number of atoms of metal and chlorine in the metal chloride. Therefore, this formula is correct for metal chlorides with a valency of 2.
Conclusion:
The correct formula for calculating the equivalent weight of metal in metal chloride depends on the valency of the metal in the compound. For metal chlorides with a valency of 2, the formula E = 8(x - y) / y is correct. However, for metal chlorides with a valency of 1, the formula for calculating the equivalent weight of the metal is more complex and depends on the specific metal and its valency.
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If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details?
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If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details?.
If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the weight of metal chloride is x gram containing y gram of metal,the equivalent weight of the metal will be 1)E=x/y×35.5. 2)E=8(y-x)/x 3)E=y × 35.5/(x-y). 4)E=8(x-y)/y pls give the answer in details?.
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