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A long solenoid has 500 turns. When current of 2A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10^(-3). The self inductance of the solenoid is?
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A long solenoid has 500 turns. When current of 2A is passed through it...
The inductance of a coil is numerically equal to the emf induced in the coil when the current in the coil changes at the rate of 1 As-1. If I is the current flowing in the circuit, then flux linked with the circuit is observed to be proportional to I, ie,

straight ϕ space proportional to space straight Istraight ϕ space equals space LI space... space left parenthesis straight i right parenthesis

where L is called the self-inductance or coefficients of self-inductance or coefficient of self-inductance or simply inductance of the coil.

Net flux through the solenoid.
Φ = 500 x 4 x 10-3 = 2 Wb
Or 2 = L x 2 [after putting value in eq. or  L = 1H]
This question is part of UPSC exam. View all NEET courses
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A long solenoid has 500 turns. When current of 2A is passed through it...
Net Flux = LI= flux passing through each turn × number of turns
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A long solenoid has 500 turns. When current of 2A is passed through it...
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A long solenoid has 500 turns. When current of 2A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10^(-3). The self inductance of the solenoid is?
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