The product of two numbers is 2028 and their H.C.F. is 13. The number ...
Let the numbers 13a and 13b.
Then, 13a * 13b = 2028
=>ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be co prime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.
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The product of two numbers is 2028 and their H.C.F. is 13. The number ...
Solution:
Given, the product of two numbers is 2028 and their H.C.F. is 13.
Let the two numbers be 13a and 13b (where a and b are co-primes)
Therefore, 13a × 13b = 2028
=> ab = 12
So, the possible pairs of (a, b) are (1, 12) and (3, 4)
Hence, the possible pairs of numbers are (13 × 1, 13 × 12) and (13 × 3, 13 × 4)
Therefore, there are two pairs of numbers whose product is 2028 and H.C.F. is 13.
Therefore, option 'B' is the correct answer.