Answer:

The formation of male gametes in flowering plants takes place through a process called meiosis. Meiosis is a type of cell division that results in the formation of four haploid cells from a single diploid cell. Each of these haploid cells contains half the number of chromosomes as the original diploid cell.

To determine the number of meiosis required for the formation of 80 male gametes in flowering plants, we need to consider the following factors:

Factors:
- The number of chromosomes in a male gamete of a flowering plant.
- The number of chromosomes in a diploid cell of a flowering plant.
- The number of haploid cells produced by each meiotic division.

Calculation:
- The number of chromosomes in a male gamete of a flowering plant is usually haploid, which means it has half the number of chromosomes as a diploid cell.
- The number of chromosomes in a diploid cell of a flowering plant can vary depending on the species, but it is typically between 20 and 40.
- Each meiotic division produces four haploid cells.

Therefore, to form 80 male gametes in flowering plants, we can use the following calculation:

- If the diploid cell has 20 chromosomes, then each haploid cell will have 10 chromosomes.
- It takes two meiotic divisions to produce four haploid cells from a single diploid cell.
- Therefore, two meiotic divisions are required to produce 80 male gametes from a single diploid cell.

Answer: Therefore, the correct answer is option (2) 10. It takes 10 meiotic divisions to produce 80 male gametes in flowering plants.

1 meiotic division gives 4 male gamates ...then no. of divisions to produce 80 males gamates is .= 80/4=20.