Two places A and B are at a certain distance. Ramu started from A towa...
40t 1 +60t 2 = d
T 1 /t 2 = 3/2
T 1 – t 2 = 2
Solving d = 480 Km
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Two places A and B are at a certain distance. Ramu started from A towa...
Given data:
Ramu's speed = 40 kmph
Raju's speed = 60 kmph
Ratio of time taken by Raju to Ramu to reach C = 2:3
To find:
Distance between A and B
Solution:
Let the distance between A and B be 'd' km.
Let us assume that Ramu and Raju met at point C after 't' hours.
Distance travelled by Ramu in 't' hours = 40t km
Distance travelled by Raju in 't' hours = 60t km
Total distance travelled by both of them to reach point C = d km
As they start from opposite directions, the sum of distances travelled by them will be equal to the distance between A and B.
Therefore, we can write:
40t + 60t = d
100t = d
We know that the ratio of time taken by Raju to Ramu to reach C is 2:3.
Let us assume that Ramu took '3x' hours to reach point C.
Therefore, Raju took '2x' hours to reach point C.
We can write:
Distance travelled by Ramu in 3x hours = 40 * 3x = 120x km
Distance travelled by Raju in 2x hours = 60 * 2x = 120x km
Both of them travelled the same distance to reach point C.
Therefore, we can write:
120x + 120x = d
240x = d
We know that 100t = d
Therefore, we can equate the values of 'd' to get:
100t = 240x
t/x = 12/5
We can now use the value of 't/x' to find the value of 't'.
Let us assume that x = 1.
Therefore, t/x = 12/5
t = 12/5
Substituting the value of 't' in the equation 100t = d, we get:
d = 100 * (12/5)
d = 240 km
Therefore, the distance between A and B is 240 km.
Hence, the correct option is (c) 480 km.