Answer:

When sodium phenoxide is heated with ethyl iodide, the reaction leads to the formation of phenetol. Let's break down the reaction and explain it in detail.

Reaction:
Sodium Phenoxide + Ethyl Iodide → Phenetol

Explanation:

1. Sodium Phenoxide:
Sodium phenoxide is the sodium salt of phenol, which is formed by reacting phenol (C6H5OH) with sodium hydroxide (NaOH). Phenol is an aromatic compound with a hydroxyl group (-OH) attached to a benzene ring. Sodium phenoxide is the conjugate base of phenol and is a white solid.

2. Ethyl Iodide:
Ethyl iodide, also known as iodoethane (C2H5I), is an alkyl halide. It is a colorless liquid that is commonly used as an alkylating agent in organic synthesis.

3. Reaction:
When sodium phenoxide reacts with ethyl iodide, an ether linkage is formed between the phenol and ethyl group. This reaction is known as Williamson ether synthesis.

4. Phenetol:
The product formed by the reaction of sodium phenoxide with ethyl iodide is phenetol. Phenetol, also known as ethoxybenzene, is an ether that consists of a benzene ring with an ethoxy (C2H5O) group attached to it. It is a clear liquid with a sweet odor.

Summary:
In summary, when sodium phenoxide is heated with ethyl iodide, the reaction leads to the formation of phenetol. Phenetol is an ether that consists of a benzene ring with an ethoxy group attached to it.

Option (a)C6H5-O-C2H5Ethylphenyl ether / Phenetole