V =220I=5A
1/R=x*1/176
therefore, R=176/x
by Ohms law, V/I=176/x
176*I/V=176*5/220
=4
therefore, 4 resistors r needed.
hope it helps u... ATB

Calculation:
To determine the number of 176 ohm resistors required to carry 5A on a 220V line, we can use Ohm's Law and the formula for calculating the total resistance in a parallel circuit.

Ohm's Law:
Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) between them. Mathematically, Ohm's Law can be expressed as:

V = I * R

Formula for Total Resistance in Parallel:
When resistors are connected in parallel, the total resistance (Rt) can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

where R1, R2, R3, ..., Rn are the individual resistances.

Step 1: Calculate the Total Resistance:
Given that the voltage (V) is 220V and the current (I) is 5A, we can rearrange Ohm's Law to solve for the resistance (R):

R = V / I

Substituting the values, we get:

R = 220V / 5A = 44 ohms

Therefore, the total resistance required to carry 5A on a 220V line is 44 ohms.

Step 2: Calculate the Number of Resistors:
Let's assume we have 'n' resistors of 176 ohms each connected in parallel. Using the formula for total resistance in parallel, we can express the equation as:

1/Rt = 1/176 + 1/176 + ... + 1/176 (n times)

Simplifying further, we get:

1/Rt = n/176

To find the value of 'n', we can rearrange the equation:

n = 176 / Rt

Substituting the value of Rt as 44 ohms, we get:

n = 176 / 44 = 4

Therefore, 4 resistors of 176 ohms each connected in parallel are required to carry 5A on a 220V line.

Summary:
To summarize, to carry 5A on a 220V line using 176 ohm resistors in parallel, we need 4 resistors. This calculation was done by using Ohm's Law to find the total resistance required and the formula for total resistance in a parallel circuit to determine the number of resistors needed.