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How many 176 ohm resistor (in parallel) are required to carry 5 ampere on a 220 volt line?
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How many 176 ohm resistor (in parallel) are required to carry 5 ampere...
For x number of resistors of resistance 176 Ω,
Here Supply voltage, V = 220 V
Current, I = 5 A
Equivalent resistance of the combination = R, given as

∴four resistors of 176 Ω are required to draw the given amount of current.
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How many 176 ohm resistor (in parallel) are required to carry 5 ampere...

Calculating the Number of 176 ohm Resistors Required

To determine the number of 176 ohm resistors needed to carry 5 amperes on a 220 volt line, we can use the formula for calculating total resistance in a parallel circuit:

Total Resistance (R_total) = 1 / (1/R1 + 1/R2 + 1/R3 + ...)

Calculating the Resistance of a Single 176 ohm Resistor

Given a single 176 ohm resistor, the resistance value (R1) is 176 ohms.

Calculating the Total Resistance for the Circuit

Using the formula mentioned above, we can calculate the total resistance of the circuit. The voltage (V) is 220 volts, and the current (I) is 5 amperes.

R_total = V / I
R_total = 220 / 5
R_total = 44 ohms

Calculating the Number of Resistors Needed

Now, we can determine the number of 176 ohm resistors required to achieve a total resistance of 44 ohms in the circuit.

1 / (1/176) = 1 / R_total
1 / (1/176) = 1 / 44
1 / 0.005681818 = 1 / 44
176 = 44

Therefore, to carry 5 amperes on a 220 volt line, a total of 4 176 ohm resistors are required in parallel.
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How many 176 ohm resistor (in parallel) are required to carry 5 ampere on a 220 volt line?
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