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Shoe the formation of Na2o transfer of electrons ?
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Shoe the formation of Na2o transfer of electrons ?
(a) A sodium atom (2, 8, 1) loses one electron to form a sodium cation. But an oxygen atom (2, 6) can become an oxide ion O2– only when it accepts 2 electrons. Thus it requires two sodium atoms to lose one electron each. In this case the doubly negative charge of oxide anion is balanced exactly by two single positively charged sodium cations. Therefore, there are two cations (Na+) to each oxygen anion (O2–) and the ratio of sodium ions to oxide ions is 2: 1. This is indicated as given below:

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Shoe the formation of Na2o transfer of electrons ?
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Shoe the formation of Na2o transfer of electrons ?
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