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A single-phase transformer has no-load loss of 64 W, as obtained from an open-circuit test.  When a short-circuit test is performed on it with 90% of the rated currents flowing in its both LV and HV windings, he measured loss is 81 W.  The transformer has maximum efficiency when operated at
  • a)
    50.0% of the rated current.
  • b)
    64.0% of the rated current.
  • c)
    80.0% of the rated current.
  • d)
    88.8% of the rated current.
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A single-phase transformer has no-load loss of 64 W, as obtained from ...
Since, the no-load loss (when load is not connected) is 64 W. So, the open circuit loss is

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Most Upvoted Answer
A single-phase transformer has no-load loss of 64 W, as obtained from ...
Given information:
- No-load loss = 64 W
- Short-circuit test loss at 90% of rated current = 81 W

To find: The current at which the transformer has maximum efficiency

Formula:
Efficiency = Output/Input = (Input - Losses)/Input = 1 - (Losses/Input)

Calculation:
Let's assume the input power to the transformer at rated current is P.
- No-load loss = Input when there is no load, so Input = 64 W
- Short-circuit test loss at 90% of rated current = Losses at rated current, so Losses = 81 W
- Therefore, P = Input + Losses = 145 W

Now, we can calculate the efficiency at different currents and find the maximum efficiency.
- At 50% of rated current, Input = 0.5P = 72.5 W, Losses = 0.05^2 * P = 3.625 W
Efficiency = 1 - (64 + 3.625)/72.5 = 87.2%
- At 64% of rated current, Input = 0.64P = 92.8 W, Losses = 0.1^2 * P = 14.5 W
Efficiency = 1 - (64 + 14.5)/92.8 = 74.9%
- At 80% of rated current, Input = 0.8P = 116 W, Losses = 0.2^2 * P = 23.2 W
Efficiency = 1 - (64 + 23.2)/116 = 70.3%
- At 88.8% of rated current, Input = 0.888P = 128.76 W, Losses = 0.3^2 * P = 34.63 W
Efficiency = 1 - (64 + 34.63)/128.76 = 64.3%

Therefore, the transformer has maximum efficiency when operated at 80% of the rated current, which is option (c).
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A single-phase transformer has no-load loss of 64 W, as obtained from an open-circuit test. When a short-circuit test is performed on it with 90% of the rated currents flowing in its both LV and HV windings, he measured loss is 81 W. The transformer has maximum efficiency when operated ata)50.0% of the rated current.b)64.0% of the rated current.c)80.0% of the rated current.d)88.8% of the rated current.Correct answer is option 'C'. Can you explain this answer?
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A single-phase transformer has no-load loss of 64 W, as obtained from an open-circuit test. When a short-circuit test is performed on it with 90% of the rated currents flowing in its both LV and HV windings, he measured loss is 81 W. The transformer has maximum efficiency when operated ata)50.0% of the rated current.b)64.0% of the rated current.c)80.0% of the rated current.d)88.8% of the rated current.Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single-phase transformer has no-load loss of 64 W, as obtained from an open-circuit test. When a short-circuit test is performed on it with 90% of the rated currents flowing in its both LV and HV windings, he measured loss is 81 W. The transformer has maximum efficiency when operated ata)50.0% of the rated current.b)64.0% of the rated current.c)80.0% of the rated current.d)88.8% of the rated current.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase transformer has no-load loss of 64 W, as obtained from an open-circuit test. When a short-circuit test is performed on it with 90% of the rated currents flowing in its both LV and HV windings, he measured loss is 81 W. The transformer has maximum efficiency when operated ata)50.0% of the rated current.b)64.0% of the rated current.c)80.0% of the rated current.d)88.8% of the rated current.Correct answer is option 'C'. Can you explain this answer?.
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